Python 按学生id对学生列表进行排序

我似乎不知道如何按学生ID对学生列表进行排序。我有一个字符串列表，每个字符串都包含学生的姓名和ID。看起来像这样：

student_list = ["John,4", "Jake,1", "Alex,10"]

["Jake,1", "John,4", "Alex,10"]

def sort_students_by_id(student_list):
    for string in student_list:
        comma = string.find(",")+1
        student = [(string[comma:])]    

        for index in range(len(student)):
            minpos = index
            for pos in range(index+1, len(student)):
                if student[pos] < student[minpos]:
                    minpos = pos
                tmp = student[index]
                student[index] = student[minpos]
                student[minpos] = tmp
            return student_list

print(sort_students_by_id(student_list))

我希望输出如下所示：

student_list = ["John,4", "Jake,1", "Alex,10"]

["Jake,1", "John,4", "Alex,10"]

def sort_students_by_id(student_list):
    for string in student_list:
        comma = string.find(",")+1
        student = [(string[comma:])]    

        for index in range(len(student)):
            minpos = index
            for pos in range(index+1, len(student)):
                if student[pos] < student[minpos]:
                    minpos = pos
                tmp = student[index]
                student[index] = student[minpos]
                student[minpos] = tmp
            return student_list

print(sort_students_by_id(student_list))

我的代码如下所示：

student_list = ["John,4", "Jake,1", "Alex,10"]

["Jake,1", "John,4", "Alex,10"]

def sort_students_by_id(student_list):
    for string in student_list:
        comma = string.find(",")+1
        student = [(string[comma:])]    

        for index in range(len(student)):
            minpos = index
            for pos in range(index+1, len(student)):
                if student[pos] < student[minpos]:
                    minpos = pos
                tmp = student[index]
                student[index] = student[minpos]
                student[minpos] = tmp
            return student_list

print(sort_students_by_id(student_list))

def按学生id排序学生（学生列表）：
对于student_列表中的字符串：
逗号=字符串。查找（“，”）+1
学生=[（字符串[逗号：）]
对于范围内的索引（len（student））：
minpos=索引
对于范围内的pos（索引+1，len（学生））：
如果学生[pos]

您只需执行以下操作：

def sort_students_by_id(student_list):
    return sorted(student_list, key=lambda s: int(s.split(',')[-1]))

 # ['Jake,1', 'John,4', 'Alex,10']
 print(sort_students_by_id(student_list))

sorted（student，key=lambda student:int（student.split（'，'）[1]））