Python代码读取csv文件并在偶数位置打印行

我有一个CSV文件

如何读取特定行

我想读偶数位置的行

给你：

import csv

even_rows = []
# reading the csv
with open("file.csv", "r+") as csv_file:
    # reading all lines
    lines = csv.reader(csv_file, delimiter=",")
    
    # extracting only even lines
    for i, line in zip(range(lines.line_num), lines):
        if i % 2 == 0:
            even_rows.append(line)

# printing output
for row in even_rows:
    print(row)

---

扩展Adrien提供的解决方案

import pandas as pd
n = 1   #Number of rows you want to skip
dataframe = pd.read_csv('your_file')
dataframe_even_rows = dataframe.iloc[::(n+1)]
dataframe_specific_row = dataframe.iloc[2] #Specific lines: read third line(index start at 0)

---

堆栈溢出不是免费的编程服务。向我们展示您已经拥有的代码！这回答了你的问题吗？

import pandas as pd

dataframe = pd.read_csv('your_file')
dataframe_even_rows = dataframe.iloc[::2]

import pandas as pd
n = 1   #Number of rows you want to skip
dataframe = pd.read_csv('your_file')
dataframe_even_rows = dataframe.iloc[::(n+1)]
dataframe_specific_row = dataframe.iloc[2] #Specific lines: read third line(index start at 0)