如何在Python中获取字典中非空值的位置

这是我的字典：

d={"1":"", "2":"", "3":"", "4":"rock" , "5":"" , "6":"" ,"7":"paper","8":""}

我想要键和值的位置，其值为非空。 我试过：

d.items()

输出：

[('1', ''), ('3', ''), ('2', ''), ('5', ''), ('4', 'rock'), ('7', 'paper'), ('6', ''), ('8', '')]

我希望我的输出是：

4 rock
7 paper

请帮忙。

像这样吗

>>> d = {"1":"", "2":"", "3":"", "4":"rock" , "5":"" , "6":"" ,"7":"paper","8":""}
>>> print {k: v for k, v in d.items() if v}
{'7': 'paper', '4': 'rock'}

d={"1":"", "2":"", "3":"", "4":"rock" , "5":"" , "6":"" ,"7":"paper","8":""}

for key, value in d.items():
    if value:
        print(key, value)

像这样

d={"1":"", "2":"", "3":"", "4":"rock" , "5":"" , "6":"" ,"7":"paper","8":""}

for key, value in d.items():
    if value:
        print(key, value)

这应该做到：

from __future__ import print_function

data = {
    '1': '', '2': '', '3': '', '4': 'rock',
    '5': '', '6': '', '7': 'paper', '8': '',
    }

new_data = {k: v for k, v in data.items() if v}

for k, v in new_data.items():
    print(k, v)

这应该做到：

from __future__ import print_function

data = {
    '1': '', '2': '', '3': '', '4': 'rock',
    '5': '', '6': '', '7': 'paper', '8': '',
    }

new_data = {k: v for k, v in data.items() if v}

for k, v in new_data.items():
    print(k, v)