python条件并计算和？

编写一个函数，根据以下评分方案比较两个DNA序列：一个匹配+1，每个连续匹配+3，每个不匹配-1

我的代码：

def pairwiseScore(seqA, seqB): 
  '''1+1+3-1-1+1+3+1-1-1+1-1-1-1'''
  print 
  signed = ''
  score = 0
  for i in range(len(seqA)):
    if(seqA[i] == seqB[i]):         
        signed += '|'
        score += 1
        if signed=='||':
            score=0
            score += 3
        else:
            score += 1

    else:
        signed += ' '
        score -=1
  return seqA+"\n"+signed+"\n"+seqB+"\n"+'score:'+ str(score)

print pairwiseScore("ATTCGT", "ATCTAT")  
print pairwiseScore("GATAAATCTGGTCT", "CATTCATCATGCAA")
print pairwiseScore('ATCG', 'ATCG')
print pairwiseScore('CATTCATCATGCAA', 'GATAAATCTGGTCT')

输出：

ATTCGT
||   |
ATCTAT
score:2

GATAAATCTGGTCT
 ||  |||  |   
CATTCATCATGCAA
score:4

ATCG
||||
ATCG
score:7  // this should be 10 because +3 for each consecutive match` 1 + 3 +3 +3 =10

CATTCATCATGCAA
 ||  |||  |   
GATAAATCTGGTCT
score:4

谁能给我小费吗

谢谢

此代码仅在签名完全等于

“| |”

时匹配

要查看最后两个字符，请尝试：

if signed[-2:] == '||':

我想你在计算分数时也有计算错误

以下是您的功能的固定和清理版本：

def pairwiseScore(seqA, seqB): 
    signed = ''
    score = 0
    for i in range(len(seqA)):
      if seqA[i] == seqB[i]:
          signed += '|'
          if signed[-2:] == '||':
              score += 3
          else:
              score += 1
      else:
          signed += ' '
          score -= 1
    return '%s\n%s\n%s\nscore:%d' % (seqA, signed, seqB, score)

---

提示：使用一致的缩进。除此之外，你有什么特别的问题吗？看看分数：7我应该得到分数：10，因为每次连续比赛+3看起来像是家庭作业。请集中你的问题。就目前的问题而言，不清楚要问什么，它将被关闭。是的，这是我试图完成的家庭作业。你在添加3分之前重置分数。例如：ATCG | | | | | ATCG分数应该是：1+3+3=10，如果你这样做，分数将是3

def pairwiseScore(seqA, seqB): 
    signed = ''
    score = 0
    for i in range(len(seqA)):
      if seqA[i] == seqB[i]:
          signed += '|'
          if signed[-2:] == '||':
              score += 3
          else:
              score += 1
      else:
          signed += ' '
          score -= 1
    return '%s\n%s\n%s\nscore:%d' % (seqA, signed, seqB, score)

def pairwiseScore(seqA, seqB): 
  '''1+1+3-1-1+1+3+1-1-1+1-1-1-1'''
  print 
  signed = ''
  score = 0
  for i in range(len(seqA)):
    if(seqA[i] == seqB[i]):         
        signed += '|'
        if i > 0 and signed[len(signed)-2]=='|':
            score += 3
        else:
            score += 1

    else:
        signed += ' '
        score -=1
  return seqA+"\n"+signed+"\n"+seqB+"\n"+'score:'+ str(score)

print pairwiseScore("ATTCGT", "ATCTAT")  
print pairwiseScore("GATAAATCTGGTCT", "CATTCATCATGCAA")
print pairwiseScore('ATCG', 'ATCG')
print pairwiseScore('CATTCATCATGCAA', 'GATAAATCTGGTCT')