Python 如何制作我的'；秘密数字游戏'；重播而不必再次执行代码？

Python初学者。我一直在尝试让我的游戏在初始游戏完成后给用户一个“再次玩”选项。如果我在6次尝试后猜不到数字，重播就可以工作，但是如果我成功地猜到数字并尝试重播，则不会发生任何事情

import random

secretNumber = random.randint(1, 20)

userGuesses = 0
userInput = False

while userInput == False:

    print("Let's play a game!")
    print("I'll think of a number between 1 and 20 and you have 6 attempts to get it right.")
    print("What is your first guess?")

    while userGuesses <= 5:

        userInput = input()

        if int(userInput) > secretNumber:
            print("Too High! Try again!")
            userGuesses += 1

        elif int(userInput) < secretNumber:
            print("Too Low! Try again!")
            userGuesses += 1

        else:
            print("Congratulations! You guessed the secret number in " + str(userGuesses + 1) + " guesses!")
            print("Would you like to play again? Y or N")
            playGame = input()
            if playGame == "Y":
                userInput = False
                userGuesses = 0
            else:
                userInput = True
                print("Goodbye!")

    else:
        print("You have run out of guesses! The number I was thinking of was " + str(secretNumber) + ". Better luck "
                                                                                                     "next time!")

    print("Would you like to play again? Y or N")
    playGame = input()

    if playGame == "Y":
        userInput = False
        userGuesses = 0
    else:
        userInput = True
        print("Goodbye!")

随机导入
secretNumber=random.randint（1,20）
用户猜测=0
userInput=False
当userInput==False时：
打印（“让我们玩个游戏吧！”）
打印（“我会想出一个介于1和20之间的数字，你有6次尝试才能把它弄对。”）
打印（“你的第一个猜测是什么？”）
当用户猜测secretNumber时：
打印（“太高！重试！”）
用户猜测+=1
elif int（用户输入）

---

提前感谢您提供的提示。

只需在“重新启动”游戏的if处添加休息时间：

import random

secretNumber = random.randint(1, 20)

userGuesses = 0
userInput = False

while userInput == False:

    print("Let's play a game!")
    print("I'll think of a number between 1 and 20 and you have 6 attempts to get it right.")
    print("What is your first guess?")

    while userGuesses <= 5:

        userInput = input()

        if int(userInput) > secretNumber:
            print("Too High! Try again!")
            userGuesses += 1

        elif int(userInput) < secretNumber:
            print("Too Low! Try again!")
            userGuesses += 1

        else:
            print("Congratulations! You guessed the secret number in " + str(userGuesses + 1) + " guesses!")
            print("Would you like to play again? Y or N")
            playGame = input()
            if playGame == "Y":
                userInput = False
                userGuesses = 0
                #Break here to exit while loop
                break
            else:
                userInput = True
                print("Goodbye!")

    else:
        print("You have run out of guesses! The number I was thinking of was " + str(secretNumber) + ". Better luck "
                                                                                                     "next time!")

    print("Would you like to play again? Y or N")
    playGame = input()

    if playGame == "Y":
        userInput = False
        userGuesses = 0
    else:
        userInput = True
        print("Goodbye!")

随机导入
secretNumber=random.randint（1,20）
用户猜测=0
userInput=False
当userInput==False时：
打印（“让我们玩个游戏吧！”）
打印（“我会想出一个介于1和20之间的数字，你有6次尝试才能把它弄对。”）
打印（“你的第一个猜测是什么？”）
当用户猜测secretNumber时：
打印（“太高！重试！”）
用户猜测+=1
elif int（用户输入）

---

希望这对你有帮助

您还可以在单独的函数中定义游戏。我会这样做：

import random

def play_game():
    secretNumber = random.randint(1, 20)

    userGuesses = 0
    userInput = False

    print("Let's play a game!")
    print("I'll think of a number between 1 and 20 and you have 6 attempts to get it right.")
    print("What is your first guess?")

    while userGuesses <= 5:
        userInput = input()

        if int(userInput) > secretNumber:
            print("Too High! Try again!")
            userGuesses += 1
        elif int(userInput) < secretNumber:
            print("Too Low! Try again!")
            userGuesses += 1
        else:
            print("Congratulations! You guessed the secret number in " + str(userGuesses + 1) + " guesses!")

    print("You have run out of guesses! The number I was thinking of was " + str(secretNumber) + ". Better luck "
                                                                                                 "next time!")


if __name__ == '__main__':            
    playGame = 'y'
    while playGame == 'y':
        play_game()
        playGame = input('Would you like to play again? [y/n] ').lower()

    print("Goodbye!")

随机导入
def play_game（）：
secretNumber=random.randint（1,20）
用户猜测=0
userInput=False
打印（“让我们玩个游戏吧！”）
打印（“我会想出一个介于1和20之间的数字，你有6次尝试才能把它弄对。”）
打印（“你的第一个猜测是什么？”）
当用户猜测secretNumber时：
打印（“太高！重试！”）
用户猜测+=1
elif int（用户输入）

只需在循环时从内部

中删除输入问题，一旦用户猜到它，就可以中断循环