Python 对数组中的特定值进行分组

假设我有这样一个数组：

namesscore = ["Rory: 1", "Rory: 4", "Liam: 5", "Liam: 6", "Erin: 8", "Liam: 2",]

我想对数组进行排序，使其如下所示：

namescore = ["Rory: 1, 4", "Liam: 5, 6, 2", "Erin: 8"]

---

我该怎么做呢？

我会迭代列表，并为每个项目在名称和分数之间进行分割。然后我会创建一个dict（更准确地说：一个

OrderedDict

，以保持顺序），并为每个名字累积分数。迭代完成后，可以将其转换为所需格式的字符串列表：

from collections import OrderedDict

def group_scores(namesscore):
    mapped = OrderedDict()
    for elem in namesscore:
        name, score = elem.split(': ')
        if name not in mapped:
            mapped[name] = []
        mapped[name].append(score)

    return ['%s%s%s' % (key, ': ', ', '.join(value)) for \
              key, value in mapped.items()]

---

似乎您需要一个使用名称作为键的字典，并为它们分配一个可以在其上使用附加的列表值。根据什么标准对最终数组进行排序？这将返回“AttributeError:“OrderedDict”对象没有属性“iteritems”@Liwa没有注意到标记，这是罪过。我编辑了

iteritems（）

调用，并将其替换为

items（）

，这应该可以在Python2和Python3上使用。这将返回“[“Luk:{'4'}”、“Luk:{'2'}”、“Luk:{'0'}”、“Luk:{'1'}”、“Rory_Follin:{'2'}”、“Rory_Follin:{'2'}”、“Rory_Follin:{'10'}”当你跑完我的prgram@Liwa你能发布你的初始

namescore

列表吗？看起来您的值和结构可能与您的示例不同。

namesscore = ["Rory: 1", "Rory: 4", "Liam: 5", "Liam: 6", "Erin: 8", "Liam: 2"]
namesscore = [tuple(el.split()) for el in namesscore]
temp = dict((el[1], el[0]) for el in namesscore)

merge = {}
for key, value in temp.iteritems():
    if value not in merge:
        merge[value] = [key]
    else:
        merge[value].append(key)

print [' '.join((k, ' '.join(v))) for k, v in merge.iteritems()]

>>> ['Rory: 1 4', 'Liam: 2 5 6', 'Erin: 8']

namesscore = ["Rory: 1", "Rory: 4", "Liam: 5", "Liam: 6", "Erin: 8", "Liam: 2",]

od = {}

[ od.setdefault(a,[]).append(b) for a,b in map(lambda x : (x[0:x.find(':')],x[-1]), namesscore)]

namesscore = ['  '.join((k,' '.join(sorted(v))))  for k, v in od.items()]

print(namesscore)

['Erin  8', 'Liam  2 5 6', 'Rory  1 4']

from collections import defaultdict
import operator

namesscore = ["Rory: 1", "Rory: 4", "Liam: 5", "Liam: 6", "Erin: 8", "Liam: 2",]

# Build a dictionary where the key is the name and the value is a list of scores
scores = defaultdict(list)
for ns in namesscore:
    name, score = ns.split(':')
    scores[name].append(score)

# Sort each persons scores
scores = {n: sorted(s) for n, s in scores.items()}   

# Sort people by their scores returning a list of tuples
scores = sorted(scores.items(), key=operator.itemgetter(1))   

# Output the final strings
scores = ['{}: {}'.format(n, ', '.join(s)) for n, s in scores]

print scores

> ['Rory:  1,  4', 'Liam:  2,  5,  6', 'Erin:  8']