在Python中从元组中减去元组的元组?
我有一个元组:在Python中从元组中减去元组的元组?,python,tuples,Python,Tuples,我有一个元组: nums = ((4, 5, 6), (5, 6, 7), (2, 3)) 现在我想创建一个类似的结构,其中每个数字从一个“基线”数字中减去。元组的基线编号为: baselines = (1, 0.5, 3) 所以我想要的结构是: # want: diffs = ((3, 4, 5), (4.5, 5.5, 6.5), (-1, 0)) 我们有: diffs[0] = [x - baselines[0] for x in nums[0]] diffs[1] = [x - b
nums = ((4, 5, 6), (5, 6, 7), (2, 3))
现在我想创建一个类似的结构,其中每个数字从一个“基线”数字中减去。元组的基线编号为:
baselines = (1, 0.5, 3)
所以我想要的结构是:
# want: diffs = ((3, 4, 5), (4.5, 5.5, 6.5), (-1, 0))
我们有:
diffs[0] = [x - baselines[0] for x in nums[0]]
diffs[1] = [x - baselines[1] for x in nums[1]]
# etc.
如何在Python中优雅地执行此操作?将
zip
与生成器表达式一起使用:
In [66]: nums = ((4, 5, 6), (5, 6, 7), (2, 3))
In [67]: baselines = (1, 0.5, 3)
In [68]: tuple( tuple( val-y for val in x ) for x,y in zip (nums,baselines ))
Out[68]: ((3, 4, 5), (4.5, 5.5, 6.5), (-1, 0))
将
zip
与生成器表达式一起使用:
In [66]: nums = ((4, 5, 6), (5, 6, 7), (2, 3))
In [67]: baselines = (1, 0.5, 3)
In [68]: tuple( tuple( val-y for val in x ) for x,y in zip (nums,baselines ))
Out[68]: ((3, 4, 5), (4.5, 5.5, 6.5), (-1, 0))
你可以这样做
>>> tuple(tuple(x-baselines[i] for x in nums[i]) for i in range(3))
((3, 4, 5), (4.5, 5.5, 6.5), (-1, 0))
你可以这样做
>>> tuple(tuple(x-baselines[i] for x in nums[i]) for i in range(3))
((3, 4, 5), (4.5, 5.5, 6.5), (-1, 0))