在列表中搜索一个值，并在python字典中找到它的键

假设字典包含这样一个列表，我想查找字典中是否存在“name”，然后在python中查找它的键。。。。。有人能帮忙吗

test_dict = { "what is your name" :['name',"what's your name",'tell me your name ?'],
              "time" : ['time','whats the time'] }

因此，搜索“name”的预期输出将类似于“what is your name”

您只需要一个，如下所示：

test_dict = { "what is your name" :['name',"what's your name",'tell me your name ?'],
              "time" : ['time','whats the time'] }

results = [k for k,v in test_dict.items() if "name" in v]

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您只需要一个[理解列表][1]，如下所示： （固定）

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如果这个名字同时包含在两个列表中呢？它对[k代表k，v在test_dict.items（）不起作用，如果v中的“nilanjan”，那么test_dict={“what is your name”：[“what's your name”，“tell me your name”，“nilanjan”]，“time”：[“time'，“what the time”，“back my code”：[“备份”，“git添加所有”]}

test_dict = { "what is your name" :['name',"what's your name",'tell me your name ?'],"time" : ['time','whats the time'] }
for t_d in test_dict:
    results = [k for k,v in t_d.items() if "name" in v]

print("100"*100)
print(results)
print("100"*100)