从Python发布时订阅不起作用
原来的问题是: 嗨 如果我从Node.js订阅Python中的发布服务器,订阅服务器将无法接收消息。另一方面,节点发布者可以同时发送python订阅服务器和节点订阅服务器,python发布者可以发送python订阅服务器 节点订户:从Python发布时订阅不起作用,python,node.js,zeromq,publish-subscribe,Python,Node.js,Zeromq,Publish Subscribe,原来的问题是: 嗨 如果我从Node.js订阅Python中的发布服务器,订阅服务器将无法接收消息。另一方面,节点发布者可以同时发送python订阅服务器和节点订阅服务器,python发布者可以发送python订阅服务器 节点订户: // Generated by LiveScript 1.4.0 (function(){ var zmq, sock; zmq = require('zmq'); sock = zmq.socket('sub'); sock.connect('tc
// Generated by LiveScript 1.4.0
(function(){
var zmq, sock;
zmq = require('zmq');
sock = zmq.socket('sub');
sock.connect('tcp://127.0.0.1:3000');
sock.subscribe('');
console.log('Subscriber connected to port 3000');
sock.on('message', function(message){
return console.log('Received a message related to: ', 'containing message: ', message.toString());
});
}).call(this);
import zmq
context = zmq.Context()
socket = context.socket(zmq.SUB)
socket.setsockopt(zmq.SUBSCRIBE, "")
socket.connect("tcp://127.0.0.1:3000")
while True:
string = socket.recv()
print string
节点发布者:
// Generated by LiveScript 1.4.0
(function(){
var zmq, sock;
zmq = require('zmq');
sock = zmq.socket('pub');
sock.bindSync('tcp://127.0.0.1:3000');
console.log('Publisher bound to port 3000');
setInterval(function(){
console.log('Sending a multipart message envelope');
return sock.send('TestMessage(node)!');
}, 1500);
}).call(this);
Python发布者
import zmq
import time
context = zmq.Context()
publisher = context.socket(zmq.PUB)
publisher.bind("tcp://127.0.0.1:3000")
while True:
time.sleep(1)
publisher.send("TestMessage")
print "Sent"
Python订户:
// Generated by LiveScript 1.4.0
(function(){
var zmq, sock;
zmq = require('zmq');
sock = zmq.socket('sub');
sock.connect('tcp://127.0.0.1:3000');
sock.subscribe('');
console.log('Subscriber connected to port 3000');
sock.on('message', function(message){
return console.log('Received a message related to: ', 'containing message: ', message.toString());
});
}).call(this);
import zmq
context = zmq.Context()
socket = context.socket(zmq.SUB)
socket.setsockopt(zmq.SUBSCRIBE, "")
socket.connect("tcp://127.0.0.1:3000")
while True:
string = socket.recv()
print string
您需要使用一个只有一个参数(即数据)的函数更改用户sock.on call: 发布者代码应该可以在不做任何修改的情况下工作,尽管我更喜欢类似Python 3的兼容代码:
import time
context = zmq.Context()
publisher = context.socket(zmq.PUB)
publisher.bind("tcp://127.0.0.1:3000")
while True:
time.sleep(1)
publisher.send(bytearray('test', 'ascii'))
print('Sent test message')
问题在于PyZMQ和zeromq.node之间的libzmq版本不匹配: 和节点版本:
$ node
> require('zmq').version
'2.2.0'
解决办法是:
卸载libzmq的当前版本:sudo apt get purge libzmq dev
卸载当前zeromq.node:sudo npm Uninstall zmq-g
安装libzmq-4.x:sudo apt get安装libzmq3 dev
如果此步骤失败,则需要从以下来源安装libzmq-4.x:
安装zeromq.node:sudo npm安装zmq
等等这段代码不适用于我的笔记本电脑,但适用于RaspberryPi!让我进一步调试…这是一个libzmq版本问题。但是你提到的代码有一个错误,现在已经修复了。非常感谢。