Python 将lambda函数用作dict值时发生奇怪的覆盖

我试图创建一个包含几个lambda函数的dict。lambda函数是numpy百分位函数。然而，我得到了奇怪的结果，好像所有的lambda函数都包含np.percentile（x，q=100）

印刷生产：

{'50_perc': <function <lambda> at 0x2cb7b90>, '70_perc': <function <lambda> at 0x2cb77d0>, '40_perc': <function <lambda> at 0x2cb75f0>, '10_perc': <function <lambda> at 0x2cb7cf8>, '30_perc': <function <lambda> at 0x2cb7500>, '0_perc': <function <lambda> at 0x2cb7aa0>, '80_perc': <function <lambda> at 0x2cb78c0>, '20_perc': <function <lambda> at 0x2cb7a28>, '100_perc': <function <lambda> at 0x2cb7848>, '90_perc': <function <lambda> at 0x2cb7758>, '60_perc': <function <lambda> at 0x2cb7d70>}
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{'50_perc'：，'70_perc'，'40_perc'，'10_perc'，'30_perc'，'0_perc'，'80_perc'，'20_perc'，'100_perc'，'90_perc'，'60_perc'：}
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就像所有lambda函数都被后续函数覆盖一样…

找到了解决方案：

一些我不太理解的后期绑定的东西。无论如何

def returnLambda(i):
    return lambda x: np.percentile(x,i)

for i in xrange(0,101,10): 
    d[str(i)+'_perc'] = returnLambda(i)
    print(i)

这是一个很好的答案

def returnLambda(i):
    return lambda x: np.percentile(x,i)

for i in xrange(0,101,10): 
    d[str(i)+'_perc'] = returnLambda(i)
    print(i)