Python 在if语句下合并两个for循环
我正在尝试将这两个代码合并在一起,以便最后一个代码可以将文本文档“Payments”附加到列表中。对于“付款”的每一行,我希望它位于Python 在if语句下合并两个for循环,python,loops,python-3.x,split,strip,Python,Loops,Python 3.x,Split,Strip,我正在尝试将这两个代码合并在一起,以便最后一个代码可以将文本文档“Payments”附加到列表中。对于“付款”的每一行,我希望它位于myList的列表中,因此它看起来像这样: myList = [['E1234','12/09/14','440','A','0']['E3431','10/01/12','320','N','120']['E0987','04/12/16','342','A','137']] 我希望能够创建最终代码,提示用户输入客户编号,然后通过myList搜索客户编号,并在屏
myList
的列表中,因此它看起来像这样:
myList = [['E1234','12/09/14','440','A','0']['E3431','10/01/12','320','N','120']['E0987','04/12/16','342','A','137']]
我希望能够创建最终代码,提示用户输入客户编号,然后通过myList
搜索客户编号,并在屏幕上显示客户的所有信息
这是两个计划中的第一个。它是最终代码的“主干”。让我们称之为:
print("Option A: Show a record\nOption Q: Quit")
decision = input("Enter A or Q: ")
if decision == "A" or decision == "a":
myFile = open("Payments.txt")
customer_number = input("Enter a customer number to view their details: ")
record = myFile.readlines()
for line in record:
if customer_number in line:
print(line)
myFile.close()
elif decision == "Q" or "q":
exit
这是第二段代码。我们称之为B:
myFile = open("Payments.txt")
myList = []
for item in myFile:
print(item.strip())
myList.append(item.strip().split(','))
myFile.close()
print(myList)
我想在if语句中插入B:if decision==“A”或decision==“A”:
我对for循环感到困惑,因为在a和B中有一个for循环,这两个循环对最终代码都至关重要。我无法将B放入A而不中断其中一个for循环
print("Option A: Show a record\nOption Q: Quit")
decision = input("Enter A or Q: ")
myList = []
if decision == "A" or decision == "a":
myFile = open("Payments.txt")
customer_number = input("Enter a customer number to view their details: ")
record = myFile.readlines()
for line in record:
for item in myFile:
print(item.strip())
myList.append(item.strip().split(','))
print(myList)
if customer_number in line:
print(line)
myFile.close()
elif decision == "Q" or "q":
exit
它显示客户编号的来源行,但不打印列表
更新
我希望能够分别打印每行的单个数据:
Customer number: E1234
Date of payment: 12/09/14
Payment amount: £440
Paid amount: £0
在你的评论中,你提到你需要附加到一个列表中,所以我修改了我的脚本,将其包括在内,但你当前的答案是分开你的a和B部分,但你必须将它们合并 逻辑是,如果一行中存在customer_编号,则将其追加到列表中,并使用循环遍历列表以打印所需内容。您的解决方案是打印整行客户详细信息,并且每隔一行打印一次
print("Option A: Show a record\nOption Q: Quit")
decision = input("Enter A or Q: ").lower()
myList = []
if decision == "a":
myFile = open("Payments.txt")
customer_number = input("Enter a customer number to view their details: ")
record = myFile.readlines()
for line in record:
if customer_number in line:
myList.append(line.strip().replace("'","").split(','))
for info in myList:
print("Customer number: ", info[0])
print("Date of payment: ", info[1])
print("Payment Amount: ", info[2])
print("Paid Amount: ", info[4])
myFile.close()
elif decision == "q":
exit()
以下是输出:
我希望能够创建提示用户输入的最终代码
客户编号,然后在myList中搜索客户编号
并在屏幕上为客户显示所有信息
我对您的代码做了一些修改,并加入了符合PEP-8标准的样板文件
def customer_payment(customer_number):
"""Edited Code. Purpose is to accept User Input for a customer number
Search for Customer Number, and if Found, Display Information about Customer.
"""
myList = []
with open("Payments.txt") as myFile:
for line in myFile:
if customer_number in line:
print(line)
for item in line:
print(item.strip())
myList.append(line.strip().split(','))
def main():
decision = input("Option A: Show a record\nOption Q: Quit\nEnter A or Q: ")
if decision.lower() == "a":
customer_number = input("Enter a customer number to view their details: ")
customer_payment(customer_number)
if __name__=="__main__":
main()
这可能需要根据Payments.txt的格式进行修改。为什么要在文件内容上循环两次?它不起作用。它打印了每一行,然后显示它将其附加到
myList
。如果我理解正确,A只打印出特定客户的详细信息,但B做什么?只需打印Payments.txt的内容?B将Payments.txt的每一行添加到myList中的单个列表中。我想在A中的if语句中包含B,这样它会将付款附加到myList中,在列表中找到customer_编号,并显示该特定行。这样做的全部目的是显示包含customer_编号的行?为什么还要费心于myList
?规则要求在此代码中使用列表来完成此工作。很抱歉,我之前没有解释。好的,我修改了我的解决方案以修复此问题,并执行您想要的操作:)您的操作正确,但打印的值不正确