Python 对Django使用clean()方法
我想知道如何在我的表单中设置一个Python 对Django使用clean()方法,python,django,django-forms,Python,Django,Django Forms,我想知道如何在我的表单中设置一个clean方法,因为我相信我的函数写得很好,但我没有克服它以获得预期的结果 我有一个简单的模型: class Document(models.Model): ... format = models.CharField(max_length=10, verbose_name=_('format'), choices=FORMAT_CHOICES, null=False, blank=False) upload = models.FileFie
clean方法
,因为我相信我的函数写得很好,但我没有克服它以获得预期的结果
我有一个简单的模型:
class Document(models.Model):
...
format = models.CharField(max_length=10, verbose_name=_('format'), choices=FORMAT_CHOICES, null=False, blank=False)
upload = models.FileField(upload_to='media/files/', validators=[validate_file_extension], verbose_name=_('document file'), null=False, blank=False)
class DocumentForm(forms.ModelForm):
def clean(self):
cleaned_data = super().clean()
upload = cleaned_data.get("upload")
file_format = upload.split(".")[-1]
format = cleaned_data.get("format")
if upload and format:
if format != file_format:
raise forms.ValidationError("Incorrect format and file format")
def __init__(self, *args, **kwargs):
super(DocumentForm, self).__init__(*args, **kwargs)
for key in self.fields:
self.fields[key].required = True
class Meta:
model = Document
fields = ['format', 'upload']
我有一张表格:
class Document(models.Model):
...
format = models.CharField(max_length=10, verbose_name=_('format'), choices=FORMAT_CHOICES, null=False, blank=False)
upload = models.FileField(upload_to='media/files/', validators=[validate_file_extension], verbose_name=_('document file'), null=False, blank=False)
class DocumentForm(forms.ModelForm):
def clean(self):
cleaned_data = super().clean()
upload = cleaned_data.get("upload")
file_format = upload.split(".")[-1]
format = cleaned_data.get("format")
if upload and format:
if format != file_format:
raise forms.ValidationError("Incorrect format and file format")
def __init__(self, *args, **kwargs):
super(DocumentForm, self).__init__(*args, **kwargs)
for key in self.fields:
self.fields[key].required = True
class Meta:
model = Document
fields = ['format', 'upload']
此方法必须检查choosen格式和文件上载扩展名是否相同。如果不是,它应该返回一个错误
我得到了这个问题:
'TemporaryUploadedFile' object has no attribute 'split'
您知道如何检查这两个字段是否正确吗?您应该拆分文件名,而不是临时上载的文件对象以获得扩展名。尝试使用upload.name获取文件名。这似乎可行,但我还有另一个问题,因此我现在可以看到预期的结果。非常感谢。