Python多处理输出
我有一个进度条功能。我想在另一个函数进行处理时运行此进度条。我使用多处理模块编写了一个简单的测试代码，但效果不好。我的代码：Python多处理输出,python,python-multiprocessing,Python,Python Multiprocessing,我有一个进度条功能。我想在另一个函数进行处理时运行此进度条。我使用多处理模块编写了一个简单的测试代码，但效果不好。我的代码： from multiprocessing import Process import time def foo(thread): print time.ctime() time.sleep(10) print time.ctime() def progress_bar(timer = 10): digits = 4 delete
from multiprocessing import Process
import time
def foo(thread):
print time.ctime()
time.sleep(10)
print time.ctime()
def progress_bar(timer = 10):
digits = 4
delete = '\b' * 6
time_slot = float(timer) / 100
for i in range(1, 101):
delete_bar = '\b' * 52
if i == 1:
bar = '|' + ' ' * 50 + '|'
else:
bar = '|' + '=' * (i / 2 - 1) + '>' + ' ' * (50 - i / 2) + '|'
print "{0}{1:{2}}{3}{4}".format(delete, str(i) + '%', digits, bar, delete_bar),
time.sleep(time_slot)
print ''
def main():
p1 = Process(target = foo1('this'))
p1.start()
p2 = Process(target = progress_bar())
p2.start()
p1.join()
p2.join()
if __name__ == "__main__":
main()
Tue Apr 5 11:49:47 2016
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Tue Apr 5 11:49:57 2016
Tue Apr 5 11:49:47 2016
Tue Apr 5 11:49:57 2016
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多谢各位 发生这种情况是因为首先计算函数参数，在定义
p1p2foo1（'This'）p1p2progress\u bar（）
有关演示这一点的简单示例，请参见以下内容：
def fn():
print 'called'
return 1
target1 = fn()
target = fn
print target1
print target
这张照片是：
>>> called # Got called as soon as you called fn via fn()
>>> 1 # Assigned the return value of fn to target1
>>> <function fn at 0x12DA77F0> # Didn't get called, assigned the fn definition to target
这张照片
Tue Apr 05 15:09:34 2016
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Tue Apr 05 15:09:44 2016
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试试这个：
from multiprocessing import Process
import time
def foo1(thread):
print time.ctime()
time.sleep(10.5)
print time.ctime()
def progress_bar(timer = 10):
digits = 4
delete = '\b' * 6
time_slot = float(timer) / 100
for i in range(1, 101):
delete_bar = '\b' * 52
if i == 1:
bar = '|' + ' ' * 50 + '|'
else:
bar = '|' + '=' * (i / 2 - 1) + '>' + ' ' * (50 - i / 2) + '|'
print "{0}{1:{2}}{3}{4}".format(delete, str(i) + '%', digits, bar, delete_bar),
time.sleep(time_slot)
print ''
def main():
p1 = Process(target=foo1, args=('this',))
# p1 = Process(target = foo1('this'))
p1.start()
time.sleep(0.1)
p2 = Process(target=progress_bar)
p2.start()
p1.join()
p2.join()
if __name__ == "__main__":
main()
请注意不同的p1进程。尝试重新运行进程
示例再次使我的计算机崩溃--问题似乎来自进程（target=foo（1））调用线路。我能够用Process（target=foo，args=（'this'，）输出正确的结果。非常感谢你！事实上，这还不是全部。在实例化第二个流程时，也需要去掉括号。有了它们，您的代码就相当于只说p1.start（）
，然后说progress\u bar（）
，它只在主进程上运行，使得第二个进程毫无意义。您可以尝试添加第三个过程来了解我的意思。@yc2986请查看答案中添加的另一个基本示例。这就是我想要的！非常感谢你！
from multiprocessing import Process
import time
def foo1(thread):
print time.ctime()
time.sleep(10.5)
print time.ctime()
def progress_bar(timer = 10):
digits = 4
delete = '\b' * 6
time_slot = float(timer) / 100
for i in range(1, 101):
delete_bar = '\b' * 52
if i == 1:
bar = '|' + ' ' * 50 + '|'
else:
bar = '|' + '=' * (i / 2 - 1) + '>' + ' ' * (50 - i / 2) + '|'
print "{0}{1:{2}}{3}{4}".format(delete, str(i) + '%', digits, bar, delete_bar),
time.sleep(time_slot)
print ''
def main():
p1 = Process(target=foo1, args=('this',))
# p1 = Process(target = foo1('this'))
p1.start()
time.sleep(0.1)
p2 = Process(target=progress_bar)
p2.start()
p1.join()
p2.join()
if __name__ == "__main__":
main()