Python 如果列表中的项与字典中子元素的列表中的项匹配

全新的蟒蛇和树桩都准备好了，将感谢一只手

testn1 = {'names':('tn1_name1','tn1_name2','tn1_name3'),'exts':('.log','.txt')}
testn2 = {'names':('tn2_name1'),'exts':('.nfo')}
testnames = {1:testn1,2:testn1}

directory = 'C:\\temp\\root\\'

for subdir in os.listdir(directory):

  # check if name of sub directory matches the name in any of the dicts in testnames[testn*]['names']
  if os.path.isdir(os.path.join(directory, subdir)) and [subdir in subdir.lower() in testnames[testn1]['names']]: # this  works but need to iterate through all dicts
    print(subdir)

    # if the a dir name matches do a recursive search for all filenames that exist in the same dict with the corresponding extensions
    for dirname, dirnames, filenames in os.walk(os.path.join(directory, subdir)):
      for file in filenames:
        if file.endswith(testnames[testn1]['exts']): # this works but need to match with corresponding folder 
          print(file)

我原以为我可以做这样的事情，但我确信我对python的理解并不是必须的

if os.path.isdir(os.path.join(directory, subdir)) and [subdir in subdir.lower() in [for testnames[key]['names'] in key, value in testnames.items()]]:

我希望保持这样的结构，但对任何事情都持开放态度

编辑：我最后和

if os.path.isdir(os.path.join(directory, subdir)) and [i for i in testnames.values() if subdir.lower() in i['names']]:

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感谢@pzp1997提供了.values上的headup，我不太确定您想要什么，但我想这就是它：

if os.path.isdir(os.path.join(directory, subdir)) and subdir.lower() in [i['names'] for i in testnames.values()]

---

这个怎么样

testn1 = {'names':('tn1_name1','tn1_name2','tn1_name3'),'exts':('.log','.txt')}
testn2 = {'names':('tn2_name1'),'exts':('.nfo')}
testnames = {1:testn1,2:testn1}

directory = 'C:\\temp\\root\\'

for dirname, _, filenames in os.walk(directory):
    the_dir =  os.path.split(dirname)[-1]
    for testn in testnames.itervalues():
        if the_dir in testn['names']:
            for file in filenames:
                _, ext = os.path.splitext(file)
                if ext in testn['exts']:
                    print the_dir, file

成功了

if os.path.isdir(os.path.join(directory, subdir)) and [i for i in testnames.values() if subdir.lower() in i['names']]:

---

有一些错误，但我现在已经测试过了。。。我不确定你到底想做什么Hi Julien，还没有走这条路，我想看看我能不能先简单地调整这一行。如果所有其他方法都失败，将重新开始。谢谢你，它似乎没有返回任何结果，我已经修改了我的帖子，希望它能澄清。