Python:while循环中的If语句

我写了一个程序，它不断滚动一个“num”边的骰子，直到它达到最大滚动，也就是你写为“num”的数字。然而，如果第一卷恰好是数字，程序不会像它应该说的那样说“你在你的数字上着陆了！”。这是密码

import random

num = () #put the number here#
i = random.randint(1,num)

while i != num:
    print(i)
    print("Not lucky")
    i = random.randint(1,num)
    if i == num:
        print("You landed on your number!")

---

同样，如果滚动等于数字选择，我得到的是“进程结束，退出代码为0”，而不是我想要的文本。如何修复此问题？

将最终打印放在

循环之外，因为您总是在那里着陆

num = 5  # put the number here#
i = random.randint(1, num)
while i != num:
    print("Not lucky,", i, "isn't the one")
    i = random.randint(1, num)
print("You landed on your number!")

将最后一次打印放在
while
循环之外，因为您总是在那里着陆

num = 5  # put the number here#
i = random.randint(1, num)
while i != num:
    print("Not lucky,", i, "isn't the one")
    i = random.randint(1, num)
print("You landed on your number!")

如果是那样呢

import random

num = int(input('Put your number: '))
i = random.randint(1, num)

while True:
    if i == num:
        print("You landed on your number!")
        print(num)
        break
    else:
        print(i)
        print("Not lucky")
        i = random.randint(1, num)

如果是那样呢

import random

num = int(input('Put your number: '))
i = random.randint(1, num)

while True:
    if i == num:
        print("You landed on your number!")
        print(num)
        break
    else:
        print(i)
        print("Not lucky")
        i = random.randint(1, num)

您可以这样做：

import random

num = (2) #put the number here#
i = random.randint(1,num)

while i != num:
    i = random.randint(1,num)
    if i != num:
        print(i, "Not lucky")


print(i, "You landed on your number!")

您可以这样做：

import random

num = (2) #put the number here#
i = random.randint(1,num)

while i != num:
    i = random.randint(1,num)
    if i != num:
        print(i, "Not lucky")


print(i, "You landed on your number!")