Python 美丽的群网垃圾…只得到文本

我在试着提取

<a href="/reviews/28th-and-b-st-skatepark/">

    28th & B St Skatepark       #This is what I'm trying to grab, just the text.

</a>

我得到了这样的回报

</a>, <a href="http://www.thrashermagazine.com/"><img alt="Thrasher Magazine Logo" src="/templates/HomePage/images/templatesImages/Header_logo.jpg" style="border:0px;"/></a>, <a href="javascript:void();" onclick="secondFunction();">Log in</a>, <a href="/Register/">Register</a>, <a href="http://www.thrashermagazine.com/"><span>Home</span></a>, <a href="http://shop.thrashermagazine.com"><span>Store</span></a>, <a href="/component/option,com_hwdvideoshare/Itemid,93/"><span>Thrasher Skateboard Magazine | Videos</span></a>, <a href="/tags/features/"><span>Features</span></a>, <a href="/component/option,com_jevents/Itemid,100/task,week.listevents/"><span>Thrasher Skateboard Magazine | Events</span></a>,

，

---

我知道这正是我要求脚本执行的操作，但我想知道是否有办法只获取我指示的文本，而不是与标记相关的所有内容。

使用

.text

属性。e、 g:

import urllib2
from BeautifulSoup import BeautifulSoup

url1 = "http://www.thrashermagazine.com/skateparks/search-results_m94/?cat=61&jr_state=CA&order=alpha&query=all"
content1 = urllib2.urlopen(url1).read()
soup = BeautifulSoup(content1)
print [e.text for e in soup.findAll('a')]

您可以随时参考

import urllib2
from BeautifulSoup import BeautifulSoup

url1 = "http://www.thrashermagazine.com/skateparks/search-results_m94/?cat=61&jr_state=CA&order=alpha&query=all"
content1 = urllib2.urlopen(url1).read()
soup = BeautifulSoup(content1)
print [e.text for e in soup.findAll('a')]