在Python中，如何从dataframe中的DateTimeIndex中删除微秒？

我想从索引中删除微秒

我的索引如下：

DatetimeIndex(['2003-11-20 13:07:40.895000+00:00',
           '2003-11-20 13:16:13.039000+00:00',
           '2003-11-20 13:24:44.868000+00:00',
           '2003-11-20 13:33:17.013000+00:00',
           '2003-11-20 13:41:49.158000+00:00',
           '2003-11-20 13:50:20.987000+00:00',
           '2003-11-20 13:58:53.132000+00:00',
           '2003-11-20 14:07:24.961000+00:00',
           '2003-11-20 14:15:57.106000+00:00',
           '2003-11-20 14:24:28.935000+00:00',
           ...
           '2003-12-04 19:28:56.025000+00:00',
           '2003-12-04 19:37:27.854000+00:00',
           '2003-12-04 19:45:59.999000+00:00',
           '2003-12-04 19:54:32.143000+00:00',
           '2003-12-04 20:03:03.972000+00:00',
           '2003-12-04 20:11:36.117000+00:00',
           '2003-12-04 20:20:07.946000+00:00',
           '2003-12-04 20:28:40.091000+00:00',
           '2003-12-04 20:37:11.920000+00:00',
           '2003-12-04 20:45:44.065000+00:00'],
          dtype='datetime64[ns, UTC]'

didx = pd.DatetimeIndex(['2003-11-20 13:07:40.895000+00:00',
           '2003-11-20 13:16:13.039000+00:00',
           '2003-11-20 13:24:44.868000+00:00',
           '2003-11-20 13:33:17.013000+00:00',
           '2003-11-20 13:41:49.158000+00:00',
           '2003-11-20 13:50:20.987000+00:00',
           '2003-11-20 13:58:53.132000+00:00',
           '2003-11-20 14:07:24.961000+00:00',
           '2003-11-20 14:15:57.106000+00:00',
           '2003-11-20 14:24:28.935000+00:00',
           '2003-12-04 19:28:56.025000+00:00',
           '2003-12-04 19:37:27.854000+00:00',
           '2003-12-04 19:45:59.999000+00:00',
           '2003-12-04 19:54:32.143000+00:00',
           '2003-12-04 20:03:03.972000+00:00',
           '2003-12-04 20:11:36.117000+00:00',
           '2003-12-04 20:20:07.946000+00:00',
           '2003-12-04 20:28:40.091000+00:00',
           '2003-12-04 20:37:11.920000+00:00',
           '2003-12-04 20:45:44.065000+00:00'],
          dtype='datetime64[ns, UTC]')

我想去掉微秒，只为了得到这样的东西：

'2003-12-0420:45:44'

我不想将其转换为字符串，因为它需要保留datetime，因为它是dataframe的索引。 我一直在寻找这个，但我只找到了这个，它不起作用：

df.index.replace(microsecond=0, inplace = True)

---

您能帮助我吗？

您应该能够在每个上使用

.strftime（“%Y-%m-%d%H:%m:%S”）

。

给定一个带有时区信息和毫秒数据的pd.DateTimeIndex，如下所示：

DatetimeIndex(['2003-11-20 13:07:40.895000+00:00',
           '2003-11-20 13:16:13.039000+00:00',
           '2003-11-20 13:24:44.868000+00:00',
           '2003-11-20 13:33:17.013000+00:00',
           '2003-11-20 13:41:49.158000+00:00',
           '2003-11-20 13:50:20.987000+00:00',
           '2003-11-20 13:58:53.132000+00:00',
           '2003-11-20 14:07:24.961000+00:00',
           '2003-11-20 14:15:57.106000+00:00',
           '2003-11-20 14:24:28.935000+00:00',
           ...
           '2003-12-04 19:28:56.025000+00:00',
           '2003-12-04 19:37:27.854000+00:00',
           '2003-12-04 19:45:59.999000+00:00',
           '2003-12-04 19:54:32.143000+00:00',
           '2003-12-04 20:03:03.972000+00:00',
           '2003-12-04 20:11:36.117000+00:00',
           '2003-12-04 20:20:07.946000+00:00',
           '2003-12-04 20:28:40.091000+00:00',
           '2003-12-04 20:37:11.920000+00:00',
           '2003-12-04 20:45:44.065000+00:00'],
          dtype='datetime64[ns, UTC]'

didx = pd.DatetimeIndex(['2003-11-20 13:07:40.895000+00:00',
           '2003-11-20 13:16:13.039000+00:00',
           '2003-11-20 13:24:44.868000+00:00',
           '2003-11-20 13:33:17.013000+00:00',
           '2003-11-20 13:41:49.158000+00:00',
           '2003-11-20 13:50:20.987000+00:00',
           '2003-11-20 13:58:53.132000+00:00',
           '2003-11-20 14:07:24.961000+00:00',
           '2003-11-20 14:15:57.106000+00:00',
           '2003-11-20 14:24:28.935000+00:00',
           '2003-12-04 19:28:56.025000+00:00',
           '2003-12-04 19:37:27.854000+00:00',
           '2003-12-04 19:45:59.999000+00:00',
           '2003-12-04 19:54:32.143000+00:00',
           '2003-12-04 20:03:03.972000+00:00',
           '2003-12-04 20:11:36.117000+00:00',
           '2003-12-04 20:20:07.946000+00:00',
           '2003-12-04 20:28:40.091000+00:00',
           '2003-12-04 20:37:11.920000+00:00',
           '2003-12-04 20:45:44.065000+00:00'],
          dtype='datetime64[ns, UTC]')

您可以使用

pd.DateTimeIndex.floor

和

tz_localize（None）

，将时间戳截断为秒，并删除时区信息

didx.floor('S').tz_localize(None)

输出：

DatetimeIndex(['2003-11-20 13:07:40', '2003-11-20 13:16:13',
               '2003-11-20 13:24:44', '2003-11-20 13:33:17',
               '2003-11-20 13:41:49', '2003-11-20 13:50:20',
               '2003-11-20 13:58:53', '2003-11-20 14:07:24',
               '2003-11-20 14:15:57', '2003-11-20 14:24:28',
               '2003-12-04 19:28:56', '2003-12-04 19:37:27',
               '2003-12-04 19:45:59', '2003-12-04 19:54:32',
               '2003-12-04 20:03:03', '2003-12-04 20:11:36',
               '2003-12-04 20:20:07', '2003-12-04 20:28:40',
               '2003-12-04 20:37:11', '2003-12-04 20:45:44'],
              dtype='datetime64[ns]', freq=None)

---

尝试

df.index.floor（'S'）

我得到这样的结果：'2003-11-20 13:07:40+00:00'那+00:00是时区信息，你不需要，然后尝试：

didx.floor（'S'）.tz_本地化（无）

尝试

df.index.astype（'datetime64[S'））

还有

idx.floor（'S'）。tz_转换（无）

。。。因此，不同之处在于，当您想要更改时区时，

tz_convert

会将时间更改为新tz中的时间，

tz_localize

会保持时间不变并只标记新tz是的，它起作用了，但它将索引转换为字符串。您能尝试一下吗？这将允许您根据需要传递datetime对象、格式，并作为datetime对象返回。所以datetime.strTime（{date\u time object}，'%Y-%m-%d%H:%m:%S'）最好有几个选项。。。这并不像斯科特的评论那样有效，但它完成了任务