Python 我怎样才能让一本词典生成两个键相同的词典
我有一本字典,什么Python 我怎样才能让一本词典生成两个键相同的词典,python,python-3.x,list,dictionary,Python,Python 3.x,List,Dictionary,我有一本字典,什么 what = {'a': ['b'], 'c': ['d\n', 'e\n', 'f'], 'd': ['f', 'g']} 并且需要将带有“/n”的项目分开,不带“/n”(顺序很重要,需要对值进行排序。): 这就是我所尝试的: def lst(profiles_file: TextIO): solve_lst = [] new_lst = fix_files(profiles_file) for k, v in ne
what = {'a': ['b'], 'c': ['d\n', 'e\n', 'f'], 'd': ['f', 'g']}
并且需要将带有“/n”的项目分开,不带“/n”(顺序很重要,需要对值进行排序。):
这就是我所尝试的:
def lst(profiles_file: TextIO):
solve_lst = []
new_lst = fix_files(profiles_file)
for k, v in new_lst.items():
for i in v:
if i.find('\n') != -1:
get_index = [v.index(i)]
solve_lst.append(get_index)
return solve_lst
我怎样才能在不做任何复杂的事情的情况下得到它呢?这里有一个使用
def lst(profiles_file: TextIO):
solve_lst = []
new_lst = fix_files(profiles_file)
for k, v in new_lst.items():
for i in v:
if i.find('\n') != -1:
get_index = [v.index(i)]
solve_lst.append(get_index)
return solve_lst
from collections import defaultdict
def lst(profiles_file: TextIO):
initial_dict = fix_files(profiles_file)
with_n = defaultdict(list)
without_n = defaultdict(list)
for k, v in initial_dict.items():
for item in v:
if '\n' in item:
with_n[k].append(item)
else:
without_n[k].append(item)
return [without_n, with_n]