Python 如何从django查询集检索项目?

Python 如何从django查询集检索项目?,python,django,view,model,django-queryset,Python,Django,View,Model,Django Queryset,我试图在queryset中获取视频元素,但检索时遇到问题 user_channel = Everything.objects.filter(profile = request.user, playlist = 'Channel') print user_channel[0] #returns the first result without error print user_channel[0]['video'] #returns error Models.py: class Every

我试图在queryset中获取视频元素,但检索时遇到问题

user_channel = Everything.objects.filter(profile = request.user, playlist = 'Channel')
print user_channel[0] #returns the first result without error   
print user_channel[0]['video'] #returns error
Models.py:

class Everything(models.Model):
    profile = models.ForeignKey(User)
    playlist = models.CharField('Playlist', max_length = 2000, null=True, blank=True)
    platform = models.CharField('Platform', max_length = 2000, null=True, blank=True)
    video = models.CharField('VideoID', max_length = 2000, null=True, blank=True)
    video_title = models.CharField('Title of Video', max_length = 2000, null=True, blank=True)
    def __unicode__(self):
        return u'%s %s %s %s %s' % (self.profile, self.playlist, self.platform, self.video, self.video_title)

用户频道[0]
不是字典。使用

user_channel[0].video

用户频道[0]
不是字典。使用

user_channel[0].video

试试这个,你会得到基于过滤器的视频列表

user_channel = Everything.objects.filter(profile = request.user, playlist = 'Channel')
video = [x.video for x in user_channel]
print video/print video[0]

试试这个,你会得到基于过滤器的视频列表

user_channel = Everything.objects.filter(profile = request.user, playlist = 'Channel')
video = [x.video for x in user_channel]
print video/print video[0]

您是否尝试了
用户频道[0]。视频
?您是否尝试了
用户频道[0]。视频