Python 处理给BeautifulSoup的坏链接的最佳方法是什么？

我正在研究从delicious中提取URL，然后使用这些URL来发现相关的提要

然而，delicious中的一些书签不是html链接，会导致BS呕吐。基本上，我想扔掉一个链接，如果BS获取它，它看起来不像html

现在，这就是我得到的

trillian:Documents jauderho$ ./d2o.py "green data center" 
processing http://www.greenm3.com/
processing http://www.eweek.com/c/a/Green-IT/How-to-Create-an-EnergyEfficient-Green-Data-Center/?kc=rss
Traceback (most recent call last):
  File "./d2o.py", line 53, in <module>
    get_feed_links(d_links)
  File "./d2o.py", line 43, in get_feed_links
    soup = BeautifulSoup(html)
  File "/Library/Python/2.5/site-packages/BeautifulSoup.py", line 1499, in __init__
    BeautifulStoneSoup.__init__(self, *args, **kwargs)
  File "/Library/Python/2.5/site-packages/BeautifulSoup.py", line 1230, in __init__
    self._feed(isHTML=isHTML)
  File "/Library/Python/2.5/site-packages/BeautifulSoup.py", line 1263, in _feed
    self.builder.feed(markup)
  File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/HTMLParser.py", line 108, in feed
    self.goahead(0)
  File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/HTMLParser.py", line 150, in goahead
    k = self.parse_endtag(i)
  File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/HTMLParser.py", line 314, in parse_endtag
    self.error("bad end tag: %r" % (rawdata[i:j],))
  File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/HTMLParser.py", line 115, in error
    raise HTMLParseError(message, self.getpos())
HTMLParser.HTMLParseError: bad end tag: u'</b  />', at line 739, column 1

---

我只需包装我的BeautifulSoup处理并查找

HTMLParser.htmlParserError

异常

import HTMLParser,BeautifulSoup
try:
    soup = BeautifulSoup.BeautifulSoup(raw_html)
    for a in soup.findAll('a'):
        href = a.['href']
        ....
except HTMLParser.HTMLParseError:
    print "failed to parse",url

但除此之外，您还可以在对页面进行爬网时检查响应的内容类型，并确保在您尝试解析页面之前，它类似于

text/html

或

application/xml+xhtml

或类似的内容。这应该可以避免大多数错误

import HTMLParser,BeautifulSoup
try:
    soup = BeautifulSoup.BeautifulSoup(raw_html)
    for a in soup.findAll('a'):
        href = a.['href']
        ....
except HTMLParser.HTMLParseError:
    print "failed to parse",url