如何使用python从AWS中存储在Secrets manager中的私钥生成OpenSSH RSA密钥？_Python_Rsa_Openssh_Aws Secrets Manager

如何使用python从AWS中存储在Secrets manager中的私钥生成OpenSSH RSA密钥？

python

如何使用python从AWS中存储在Secrets manager中的私钥生成OpenSSH RSA密钥？,python,rsa,openssh,aws-secrets-manager,Python,Rsa,Openssh,Aws Secrets Manager,我有以下代码，生成putty生成并存储在AWS secret manager中的密钥的公共和私有行的json： import boto3 import base64 from botocore.exceptions import ClientError def get_secret(): secret_name = "Server/Name" region_name = "us-west-1" # Create a Secrets

我有以下代码，生成putty生成并存储在AWS secret manager中的密钥的公共和私有行的json：

import boto3
import base64
from botocore.exceptions import ClientError
def get_secret():
    secret_name = "Server/Name"
    region_name = "us-west-1"
    # Create a Secrets Manager client
    session = boto3.session.Session()
    client = session.client(
        service_name='secretsmanager',
        region_name=region_name
    )
    # In this sample we only handle the specific exceptions for the 'GetSecretValue' API.
    # See https://docs.aws.amazon.com/secretsmanager/latest/apireference/API_GetSecretValue.html
    # We rethrow the exception by default.
    try:
        get_secret_value_response = client.get_secret_value(
            SecretId=secret_name
        )
    except ClientError as e:
        if e.response['Error']['Code'] == 'DecryptionFailureException':
            # Secrets Manager can't decrypt the protected secret text using the provided KMS key.
            # Deal with the exception here, and/or rethrow at your discretion.
            raise e
        elif e.response['Error']['Code'] == 'InternalServiceErrorException':
            # An error occurred on the server side.
            # Deal with the exception here, and/or rethrow at your discretion.
            raise e
        elif e.response['Error']['Code'] == 'InvalidParameterException':
            # You provided an invalid value for a parameter.
            # Deal with the exception here, and/or rethrow at your discretion.
            raise e
        elif e.response['Error']['Code'] == 'InvalidRequestException':
            # You provided a parameter value that is not valid for the current state of the resource.
            # Deal with the exception here, and/or rethrow at your discretion.
            raise e
        elif e.response['Error']['Code'] == 'ResourceNotFoundException':
            # We can't find the resource that you asked for.
            # Deal with the exception here, and/or rethrow at your discretion.
            raise e
    else:
        # Decrypts secret using the associated KMS CMK.
        # Depending on whether the secret is a string or binary, one of these fields will be populated.
        if 'SecretString' in get_secret_value_response:
            secret = get_secret_value_response['SecretString']
        else:
            decoded_binary_secret = base64.b64decode(get_secret_value_response['SecretBinary'])
    return json.loads(secret)

key = get_secret()
print(key)

当前的JSON输出是

{'Key': 'PuTTY-User-Key-File-2: ssh-rsa Encryption: none Comment: rsa-key-20200608 Public-Lines: 6 AAAAB3NzaC1yc2EAAAABJQAAAQEA9CfhCMQOh0OCjzQsgpceJwklTtKJYOZLpl02 ********publicLines********* 
Private-Lines: 14 r1ePzc1522MZrfWYn3t7sBhLWA26jqMTWeqSkflnW1MMGay8fpkiTpVZPnX7Oe5L +hgkHZSJDgyzHpkA22XqQgi6uAfK7lugTCkYfq3n4xVU3U+ CzNr+kuMxNRoJBOyU ********privateLines*********'}

但是我想为我的私有线路生成OpenSSH RSA格式密钥

预期产出为：

您可以将已经编码的密钥存储为字符串，而不使用JSON包装它们。请参阅存储私钥的示例。

您可以将已编码的密钥存储为字符串，而不将其包装为JSON。请参见存储私钥的示例