Python 如何允许只输入字符串值";停止“&引用&引用;,然后检查并转换为float
嗨,我的循环结束时遇到了问题。我需要将输入作为字符串接受,以获取“stop”或“”,但我不需要任何其他字符串输入。输入被转换为float,然后添加到列表中,但是如果用户键入“bob”,我会得到转换错误,并且我不能设置输入(float),因为这样我就不能接受“stop” 完整的当前代码如下 我目前的想法如下:Python 如何允许只输入字符串值";停止“&引用&引用;,然后检查并转换为float,python,python-3.x,Python,Python 3.x,嗨,我的循环结束时遇到了问题。我需要将输入作为字符串接受,以获取“stop”或“”,但我不需要任何其他字符串输入。输入被转换为float,然后添加到列表中,但是如果用户键入“bob”,我会得到转换错误,并且我不能设置输入(float),因为这样我就不能接受“stop” 完整的当前代码如下 我目前的想法如下: 检查“停止” 检查输入是否为浮点数 如果不是1或2,则请求有效输入 有什么想法吗?如果是简单的,就给我指个方向,我会试着把它翻出来。否则 谢谢 # Write a progam that a
# Write a progam that accepts an unlimited number of input as integers or floating point.
# The input ends either with a blank line or the word "stop".
mylist = []
g = 0
total = 0
avg = 0
def calc():
total = sum(mylist);
avg = total / len(mylist);
print("\n");
print ("Original list input: " + str(mylist))
print ("Ascending list: " + str(sorted(mylist)))
print ("Number of items in list: " + str(len(mylist)))
print ("Total: " + str(total))
print ("Average: " + str(avg))
while g != "stop":
g = input()
g = g.strip() # Strip extra spaces from input.
g = g.lower() # Change input to lowercase to handle string exceptions.
if g == ("stop") or g == (""):
print ("You typed stop or pressed enter") # note for testing
calc() # call calculations function here
break
# isolate any other inputs below here ????? ---------------------------------------------
while g != float(input()):
print ("not a valid input")
mylist.append(float(g))
我认为蟒蛇式的方式应该是:
def calc(mylist): # note the argument
total = sum(mylist)
avg = total / len(mylist) # no need for semicolons
print('\n', "Original list input:", mylist)
print("Ascending list:", sorted(mylist))
print ("Number of items in list:", len(mylist))
print ("Total:", total)
print ("Average:", avg)
mylist = []
while True:
inp = input()
try:
mylist.append(float(inp))
except ValueError:
if inp in {'', 'stop'}:
calc(mylist)
print('Quitting.')
break
else:
print('Invalid input.')
我认为蟒蛇式的方式应该是:
def calc(mylist): # note the argument
total = sum(mylist)
avg = total / len(mylist) # no need for semicolons
print('\n', "Original list input:", mylist)
print("Ascending list:", sorted(mylist))
print ("Number of items in list:", len(mylist))
print ("Total:", total)
print ("Average:", avg)
mylist = []
while True:
inp = input()
try:
mylist.append(float(inp))
except ValueError:
if inp in {'', 'stop'}:
calc(mylist)
print('Quitting.')
break
else:
print('Invalid input.')
谢谢,效果很好。按照我的理解,将其分解。在获得输入后,它将尝试将值作为浮点值附加。如果它无法附加,则将其捕获为ValueError。Exception,If允许通过特殊条件。谢谢,效果很好。按照我的理解将其分解。在获得输入后,它将将尝试将该值附加为浮点值。如果无法附加,则将其捕获为ValueError。Exception、If允许通过特殊条件。