Python 无法使用xhtml2pdf（返回错误的文件url）获取要转换为pdf的图像

我找到了一个假定的解决方案

我正试图实施它，但我不能这样做

这是我目前的代码：

utils.py

from io import BytesIO
from django.http import HttpResponse
from django.template.loader import get_template

from xhtml2pdf import pisa

def render_to_pdf(template_src, context_dict={}):
     template = get_template(template_src)
     html  = template.render(context_dict)
     result = BytesIO()
     pdf = pisa.pisaDocument(BytesIO(html.encode("ISO-8859-1")), result, link_callback=fetch_resources)
     if not pdf.err:
          return HttpResponse(result.getvalue(), content_type='application/pdf')
     return None

def fetch_resources(uri, rel):
    path = os.path.join(settings.MEDIA_ROOT, uri.replace(settings.MEDIA_URL, ""))

    return path

 from django.http import HttpResponse
 from django.views.generic import View

 from yourproject.utils import render_to_pdf #created in step 4

 class GeneratePdf(View):
     def get(self, request, *args, **kwargs):
         data = {
              'today': datetime.date.today(), 
              'amount': 39.99,
             'customer_name': 'Cooper Mann',
             'order_id': 1233434,
         }
         pdf = render_to_pdf('pdf/invoice.html', data)
         return HttpResponse(pdf, content_type='application/pdf')

视图.py

from io import BytesIO
from django.http import HttpResponse
from django.template.loader import get_template

from xhtml2pdf import pisa

def render_to_pdf(template_src, context_dict={}):
     template = get_template(template_src)
     html  = template.render(context_dict)
     result = BytesIO()
     pdf = pisa.pisaDocument(BytesIO(html.encode("ISO-8859-1")), result, link_callback=fetch_resources)
     if not pdf.err:
          return HttpResponse(result.getvalue(), content_type='application/pdf')
     return None

def fetch_resources(uri, rel):
    path = os.path.join(settings.MEDIA_ROOT, uri.replace(settings.MEDIA_URL, ""))

    return path

 from django.http import HttpResponse
 from django.views.generic import View

 from yourproject.utils import render_to_pdf #created in step 4

 class GeneratePdf(View):
     def get(self, request, *args, **kwargs):
         data = {
              'today': datetime.date.today(), 
              'amount': 39.99,
             'customer_name': 'Cooper Mann',
             'order_id': 1233434,
         }
         pdf = render_to_pdf('pdf/invoice.html', data)
         return HttpResponse(pdf, content_type='application/pdf')

如果我只是渲染一个普通模板，那么所有内容都会正确加载，因此我知道这部分过程存在问题。invoice.html模板包括一个url，如/home/images/products/1231

<img src='{{ photo.url }}'>

---

无需设置获取资源。它对我有用

def render_to_pdf(template_src, context_dict={}):
    template = get_template(template_src)
    html = template.render(context_dict)
    result = BytesIO()
    pdf = pisa.pisaDocument(BytesIO(html.encode("ISO-8859-1")), result)
    if not pdf.err:
     return HttpResponse(result.getvalue(), content_type='application/pdf')
    return None

---

另外，请尝试参考此链接，以呈现pdf中的图像。您需要使用以下函数进行图像回调：

def link_callback(uri, rel):
    """
    Convert HTML URIs to absolute system paths so xhtml2pdf can access those
    resources
    """
    # use short variable names
    sUrl = settings.STATIC_URL      # Typically /static/
    sRoot = settings.STATIC_ROOT    # Typically /home/userX/project_static/
    mUrl = settings.MEDIA_URL       # Typically /static/media/
    mRoot = settings.MEDIA_ROOT     # Typically /home/userX/project_static/media/

    # convert URIs to absolute system paths
    if uri.startswith(mUrl):
        path = os.path.join(mRoot, uri.replace(mUrl, ""))
    elif uri.startswith(sUrl):
        path = os.path.join(sRoot, uri.replace(sUrl, ""))
    else:
        return uri  # handle absolute uri (ie: http://some.tld/foo.png)

    # make sure that file exists
    if not os.path.isfile(path):
            raise Exception(
                'media URI must start with %s or %s' % (sUrl, mUrl)
            )
    return path

接下来添加渲染函数

链接：

---

如果此答案对您有帮助，请将其标记为答案。

您是否也在渲染图像？我有这个确切的代码，但它不起作用。如果是的话，你的视图是什么样子的？你的视图是什么样子的？你可以参考我给你的一个linkBro，这就是我使用的教程。即使在他的youtube评论中，他也承认没有渲染图像。它会返回任何错误吗？如果是，它会显示什么错误？警告必须是有效的URL。您可以在html页面上呈现图像吗？