如何在python中指定windows服务

我正在编写一个用python启动和停止windows服务的脚本。到目前为止，我已经将其设置为可以打开/关闭任何列出的服务，但是如果列出的服务无效，我将尝试进行循环。我在计算机上创建了一个包含所有列出的服务的文本文件。我正在尝试创建一个检查是否是一个真正的服务。我的启动/停止服务语法是

choice = input (" Would you like to start or stop a service : ")

if choice == "stop" :

    stopping = 1

   while stopping == 1:

       service_name = input (' Which service would you like to stop : ')

        win32serviceutil.StopService(service_name)

        print ("Service is stopping")

        text = ". . . . . . "

        for char in text:

            sys.stdout.write(char)

            time.sleep(0.5)

        print ( "Service has stopped" )

        break

serviceList = r"C:\Users\ethanm\Desktop\Python Text Files\Windows 
Services List.txt "

inFile = open(serviceList, 'r')

line = inFile.read()

serviceList = line.split()

print (serviceList)

serviceWord = input ("enter a service")

if serviceWord in open (r"C:\Users\ethanm\Desktop\Python Text 
Files\Windows Services List.txt ").read():

    print ("word found")

else:

    print ("no word")

enter a service : okay

word found 

enter a service : spooler

word found

enter a service : anifd

no word

enter a service : aeiou 

no word

enter a service : shpamsvc

word found

而我的支票是

choice = input (" Would you like to start or stop a service : ")

if choice == "stop" :

    stopping = 1

   while stopping == 1:

       service_name = input (' Which service would you like to stop : ')

        win32serviceutil.StopService(service_name)

        print ("Service is stopping")

        text = ". . . . . . "

        for char in text:

            sys.stdout.write(char)

            time.sleep(0.5)

        print ( "Service has stopped" )

        break

serviceList = r"C:\Users\ethanm\Desktop\Python Text Files\Windows 
Services List.txt "

inFile = open(serviceList, 'r')

line = inFile.read()

serviceList = line.split()

print (serviceList)

serviceWord = input ("enter a service")

if serviceWord in open (r"C:\Users\ethanm\Desktop\Python Text 
Files\Windows Services List.txt ").read():

    print ("word found")

else:

    print ("no word")

enter a service : okay

word found 

enter a service : spooler

word found

enter a service : anifd

no word

enter a service : aeiou 

no word

enter a service : shpamsvc

word found

无论何时我使用该检查，它在技术上都是有效的，但是如果我键入一个字符，它将被列为正确的，因为该字符可以在任何服务中找到。例如

choice = input (" Would you like to start or stop a service : ")

if choice == "stop" :

    stopping = 1

   while stopping == 1:

       service_name = input (' Which service would you like to stop : ')

        win32serviceutil.StopService(service_name)

        print ("Service is stopping")

        text = ". . . . . . "

        for char in text:

            sys.stdout.write(char)

            time.sleep(0.5)

        print ( "Service has stopped" )

        break

serviceList = r"C:\Users\ethanm\Desktop\Python Text Files\Windows 
Services List.txt "

inFile = open(serviceList, 'r')

line = inFile.read()

serviceList = line.split()

print (serviceList)

serviceWord = input ("enter a service")

if serviceWord in open (r"C:\Users\ethanm\Desktop\Python Text 
Files\Windows Services List.txt ").read():

    print ("word found")

else:

    print ("no word")

enter a service : okay

word found 

enter a service : spooler

word found

enter a service : anifd

no word

enter a service : aeiou 

no word

enter a service : shpamsvc

word found

当我输入一个普通字符时

enter a service : a

word found

我希望脚本能够判断它是否是有效的服务，只接受有效的服务输入。例如

choice = input (" Would you like to start or stop a service : ")

if choice == "stop" :

    stopping = 1

   while stopping == 1:

       service_name = input (' Which service would you like to stop : ')

        win32serviceutil.StopService(service_name)

        print ("Service is stopping")

        text = ". . . . . . "

        for char in text:

            sys.stdout.write(char)

            time.sleep(0.5)

        print ( "Service has stopped" )

        break

serviceList = r"C:\Users\ethanm\Desktop\Python Text Files\Windows 
Services List.txt "

inFile = open(serviceList, 'r')

line = inFile.read()

serviceList = line.split()

print (serviceList)

serviceWord = input ("enter a service")

if serviceWord in open (r"C:\Users\ethanm\Desktop\Python Text 
Files\Windows Services List.txt ").read():

    print ("word found")

else:

    print ("no word")

enter a service : okay

word found 

enter a service : spooler

word found

enter a service : anifd

no word

enter a service : aeiou 

no word

enter a service : shpamsvc

word found

方法1： 将服务列表存储在阵列中

services=['hello'，'world']
服务中的“你好”
>真的
“他”在服役
>假的

如果正在读取的文本文件中有服务列表，请尝试使用string方法创建一个要使用的数组

方法2： 在当前代码中添加一个

如果输入（“您想启动或停止服务吗？”：”。下一个（）是“停止”：
尽管如此：
服务名称=输入（'要停止的服务：'）
尝试：
打印（“服务正在停止…”）
win32serviceutil.StopService（服务名称）
打印（“服务已停止”）
打破
除：
打印（“无效服务”）

您是否尝试在计算机中获取所有服务的名称并将其放入列表中，然后查看其中是否存在输入？这就是我所做的。我将其设置为打印列表中所有服务名称的位置，名称为Windows服务列表。但是，是的，问题还在继续发生，我得到了一个想法，使用批处理文件来简化这个过程，我正在尝试为什么不使用

psutil

？这肯定也可以。我只是想在这里使用win32serviceutil模块。您好，谢谢您的想法。如果我没有293个服务可以输入，这可能会起作用。但我肯定会把这当作最后的选择，其他给我的想法都不管用。例外情况非常好，非常感谢。