Python 请告诉我如何使此代码更;蟒蛇的;
此代码功能齐全,无需使用错误处理。有没有更有效的方法来写这个?我很想向你们大家学习Python 请告诉我如何使此代码更;蟒蛇的;,python,python-3.x,loops,Python,Python 3.x,Loops,此代码功能齐全,无需使用错误处理。有没有更有效的方法来写这个?我很想向你们大家学习 from getpass import getpass username = input("Username: ") grant_access = False while not grant_access: password = getpass("Password: ") if password == 'pass123': grant_access = True elif password
from getpass import getpass
username = input("Username: ")
grant_access = False
while not grant_access:
password = getpass("Password: ")
if password == 'pass123':
grant_access = True
elif password != 'pass123':
while not grant_access:
password = getpass("Re-enter Password: ")
if password == 'pass123':
grant_access = True
elif password != 'pass123':
continue
print("Logging in...")
你可以这样做:
from getpass import getpass
username = input("Username: ")
password = getpass("Password: ")
if password != 'pass123':
while True:
password = getpass("Re-enter Password: ")
if password == 'pass123':
break
print("Logging in...")
甚至像这样:
from getpass import getpass
username = input("Username: ")
password = getpass("Password: ")
while password != 'pass123':
password = getpass("Re-enter Password: ")
print("Logging in...")
此问题最好在上收到。可能与的重复。为什么在if中需要一段时间?只需使用密码!='pass123':。我忘了是什么时候添加的:=的,但那感觉像是一个很好的地方。尼斯提示,改变了这一点。