python webapp2嵌套路径前缀路由
是否有一种简单的方法来构建webapp2的url,这种方法允许下面这样的结构?我看不到从父级传递PathPrefixRoute的方法,但是像PathPrefixRoute“/v1”、[PathPrefixRoute'$1/app1'之类的东西会很酷python webapp2嵌套路径前缀路由,python,webapp2,Python,Webapp2,是否有一种简单的方法来构建webapp2的url,这种方法允许下面这样的结构?我看不到从父级传递PathPrefixRoute的方法,但是像PathPrefixRoute“/v1”、[PathPrefixRoute'$1/app1'之类的东西会很酷 urls = [ PathPrefixRoute('/v1', [ PathPrefixRoute('/app1', [ # /v1/app1/index Route('/i
urls = [
PathPrefixRoute('/v1', [
PathPrefixRoute('/app1', [
# /v1/app1/index
Route('/index', 'v1.app1.index.Main')
]),
PathPrefixRoute('/app2', [
# /v1/app2/index
Route('/index', 'v1.app2.index.Main')
])
]),
PathPrefixRoute('/v2', [
PathPrefixRoute('/app1', [
# /v2/app1/index
Route('/index', 'v2.app1.index.Main')
])
])
]
application = webapp2.WSGIApplication(routes=urls)
最后,我在uwsgi上编写了自己的定制服务器。我使用的路由机制已粘贴在下面,但完整的应用程序是318行,可以处理100个RPS,这是我测试的全部内容,但感觉它可以在基本的1核服务器上处理1000个RPS 请随意评论好的、坏的和丑陋的想法
class Static:
def __init__(self, s): self._s = s
def __str__(self): return self._s
SITES = {
'(127.0.0.1|localhost)': {
'/': 'default.index.Home'
},
'(example.com)': {
'/': 'example.index.Home',
'/static': Static('example'),
'/console': {
'/': 'example.console.Home',
'/login': 'example.console.Login'
}
}
}
def get_location(self):
http_host = self.env.get('HTTP_HOST', '').split(':')[0] # host:port
if not http_host: raise HttpException(404, "Empty Site")
path_info = self.env.get('PATH_INFO')
if not path_info: raise HttpException(404, "Empty Path")
for site in SITES:
if re.match(site, http_host, re.I):
paths = SITES[site]
parts = path_info.split('/')[1:] # first is always blank
for part in parts:
p = paths.copy()
for path in p:
if re.match(path + '$', '/' + part, re.I):
if isinstance(p[path], basestring):
return p[path]
paths = p[path]
break
paths = None
if not paths: break
raise HttpException(404, "Unknown Path")
raise HttpException(404, "Unknown Site")