Python Discord.py Cog无法接受内容参数
所以我现在在discord.py中,每当我直接编辑bot.py(我的主文件)时,我都可以实现一个版本的suggest命令Python Discord.py Cog无法接受内容参数,python,discord.py,Python,Discord.py,所以我现在在discord.py中,每当我直接编辑bot.py(我的主文件)时,我都可以实现一个版本的suggest命令 @bot.command(name = 'suggest', help = 'Use this command to give a suggestion to the server') async def suggest(ctx, content): channel = discord.utils.get(bot.guilds[0].channels, name =
@bot.command(name = 'suggest', help = 'Use this command to give a suggestion to the server')
async def suggest(ctx, content):
channel = discord.utils.get(bot.guilds[0].channels, name = 'suggestions')
print('Suggest command triggered, content is {}'.format(content))
await channel.send(content)
^bot只是我的客户端版本
这非常好(除了我只得到第一个单词的内容,所以如果有人能解决这个问题,那也很好)
但当我复制粘贴到我的齿轮
@commands.command(name = 'suggest', help = 'Use this command to give a suggestion to the server')
async def suggest(self, bot, ctx, content):
print('Suggest command triggered')
channel = discord.utils.get(bot.guilds[0].channels, name = 'suggestions')
print('Content is {}'.format(content))
await channel.send(content)
它不工作,有人能帮我吗?对于cog来说,
bot
参数是不必要的,所以您只需要
@commands.command(name = 'suggest', help = 'Use this command to give a suggestion to the server')
async def suggest(self, ctx, content):
print('Suggest command triggered')
channel = discord.utils.get(bot.guilds[0].channels, name = 'suggestions')
print('Content is {}'.format(content))
await channel.send(content)
对于只包含第一个单词的参数,discord.py按单词分隔参数,因此您可以使用*
将它们分组,如下所示:
async def suggest(self, ctx, *content): # gets all the words in a tuple