Python 检查数字是否在范围内并输出到文件

我正在尝试制作一个程序，自动为我排序

我有一个不同的机器人与点列表。看起来有点像这样：

BOT#1 |积分余额=39 |积分收入=2000

我希望python打开我的文件（列表），遍历列表并根据它们的值输出机器人 所以我看起来像这样

BOT#1 | POINTS BALANCE = 100 | POINTS EARNED = 2000
BOT#2 | POINTS BALANCE = 200 | POINTS EARNED = 2023
BOT#3 | POINTS BALANCE = 300 | POINTS EARNED = 9300
BOT#4 | POINTS BALANCE = 400 | POINTS EARNED = 1030

对于每100个点，python将生成一个新文件，并将所有具有这些点的机器人放在其中（整行）

所以

BOT#1 |积分余额=100 |积分收入=2000

将进入一个名为“100”的文件，python将把整行写入新文件

如果这让人困惑，我很抱歉，我真的不知道从哪里开始，我很难解释

tldr： 我希望python打开我的文件，浏览列表并为

积分平衡=价值

然后每100次，它生成一个新文件，并将原始文件中的整行内容写入其中。

您可以尝试以下方法：

t = ['BOT#1 | POINTS BALANCE = 100 | POINTS EARNED = 2000', 'BOT#2 | POINTS BALANCE = 200 | POINTS EARNED = 2023', 'BOT#3 | POINTS BALANCE = 300 | POINTS EARNED = 9300', 'BOT#4 | POINTS BALANCE = 400 | POINTS EARNED = 1030']
t = [line.replace("BOT#", "").replace("POINTS BALANCE =", "").replace("POINTS EARNED =","").split("|") for line in t]
t = np.array(t).astype(int)
points_balance = np.unique(t[:,1])
by_point = {}
for p in points_balance:
    rows = t[t[:,1]==p]
    rows = ["BOT#{} | POINTS BALANCE = {} | POINTS EARNED = {}".format(*row) for row in rows]
    by_point[p] = rows

输出将是平衡点所在行的字典，您可以将它们中的每一行写入一个文件

{100: ['BOT#1 | POINTS BALANCE = 100 | POINTS EARNED = 2000'], 200: ['BOT#2 | POINTS BALANCE = 200 | POINTS EARNED = 2023'], 300: ['BOT#3 | POINTS BALANCE = 300 | POINTS EARNED = 9300'], 400: ['BOT#4 | POINTS BALANCE = 400 | POINTS EARNED = 1030']}

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一如既往，发布一些代码！