pythonoop：扩展类

版本：python3.6.1

源代码：

class ContactList(list):
    def search(self,name):
    '''Return all contacts that contain the search value in their name.'''
        matching_contacts = []
        for contact in self:
            if name in contact.name:
                matching_contacts.append(contact)
            return matching_contacts

class Contact:
    all_contacts = ContactList()
    def __init__(self,name,email):
        self.name = name
        self.email = email
        Contact.all_contacts.append(self)

然后空转

c1 = Contact("John A","johna@example.com")
c2 = Contact("John B","johnb@example.com")
c3 = Contact("Jenna C","jennac@example.com")
[c.name for c in Contact.all_contacts.search('John')]

结果应该是

['John A'，'John B']

，但我的空闲显示为

['John A']

我想知道我的代码出了什么问题

那是因为你的“返回”位置不对

class ContactList(list):
def search(self,name):
'''Return all contacts that contain the search value in their name.'''
    matching_contacts = []
    for contact in self:
        if name in contact.name:
            matching_contacts.append(contact)
    return matching_contacts

---

为什么联系人首先会知道联系人列表？不要从内置扩展，使用ABC模块。

返回匹配的联系人的缩进是错误的；它需要在循环之外。并且您正在大量混合实例和类成员…found=[如果item中的“John”，则所有_联系人中的item对应item]