当第一个进程在python3中完成时,如何终止并行进程?
问题:当流程1完成时,如何停止流程2 更长的版本:我制作了一个脚本,可以多处理2个函数,我真的不知道如何在第一个进程完成后停止第二个进程 我的代码:当第一个进程在python3中完成时,如何终止并行进程?,python,python-3.x,process,multiprocessing,terminate,Python,Python 3.x,Process,Multiprocessing,Terminate,问题:当流程1完成时,如何停止流程2 更长的版本:我制作了一个脚本,可以多处理2个函数,我真的不知道如何在第一个进程完成后停止第二个进程 我的代码: def printHelloWorld(): # So this takes 5.0053 seconds to completly run print("Hello World.") time.sleep(5) print("Hello World. (after 5 seconds)&quo
def printHelloWorld(): # So this takes 5.0053 seconds to completly run
print("Hello World.")
time.sleep(5)
print("Hello World. (after 5 seconds)")
def printText(): # And this takes 10.0102 seconds to completly run
print("Some text.")
time.sleep(10)
print("Some text. (after 10 seconds)")
if __name__ == "__main__": # I multiprocessed these 2 functions to reduce time.
# But what I actually want is to terminate process 2 when process 1 has finished.
p1 = Process(target = printHelloWorld)
p2 = Process(target = printText)
p1.start()
p2.start()
p1.join()
p2.join()
我尝试了一个while循环来检查何时p1.is_alive==False
,然后我应该终止进程2,但它不起作用。我也搜索了答案,但没有找到符合我要求的答案
谢谢你的阅读/回答
让我澄清一些事情:如果我不能正确解释,我很抱歉,但我想问的是,既然不再需要,我如何检查哪一个已经完成了第一个过程并终止第二个过程
示例:如果我们不知道函数1和2的执行时间(两个函数都在并行进程中),该怎么办。因此,一旦第一个进程停止,我希望另一个进程停止。我该怎么做?我希望现在能清楚地描述这一点。再次为混乱感到抱歉 您是否尝试了
过程。是否终止
import time
from multiprocessing import Process
def printHelloWorld(): # So this takes 5.0053 seconds to completly run
print("Hello World.")
time.sleep(5)
print("Hello World. (after 5 seconds)")
def printText(): # And this takes 10.0102 seconds to completly run
print("Some text.")
time.sleep(10)
print("Some text. (after 10 seconds)")
if __name__ == "__main__": # I multiprocessed these 2 functions to reduce time.
# But what I actually want is to terminate process 2 when process 1 has finished.
p1 = Process(target = printHelloWorld)
p2 = Process(target = printText)
p1.start()
p2.start()
p1.join()
p2.terminate() # terminate process 2
p2.join()
我建议你们利用图书馆。它包装了Python的标准库线程和多处理对象。但是它很有可能取消正在运行的呼叫
import time
from concurrent.futures import wait, FIRST_COMPLETED
from pebble import ProcessPool
def printHelloWorld(): # So this takes 5.0053 seconds to completly run
print("Hello World.")
time.sleep(5)
print("Hello World. (after 5 seconds)")
def printText(): # And this takes 10.0102 seconds to completly run
print("Some text.")
time.sleep(10)
print("Some text. (after 10 seconds)")
if __name__ == "__main__": # I multiprocessed these 2 functions to reduce time.
with ProcessPool(max_workers=2) as pool:
f1 = pool.schedule(printHelloWorld)
f2 = pool.schedule(printText)
done, not_done = wait((f1, f2), return_when=FIRST_COMPLETED)
for f in not_done:
f.cancel()
您不需要while循环-等待p1
完成正是p1.join()
为您所做的-它在等待时不会占用CPU。您能澄清您的问题吗?您可以在p1
完成后直接执行p2
,即p2.terminate()
在p1.join()
之后。阅读Hi!是的,我做了,但是再次检查我的编辑。很抱歉没有解释清楚。