文本游戏-将输入文本转换为小写-Python 3.0

（（作为对上述编辑的回应，上述链接中未回答此问题。上述问题与我的预期用途无关。）

我读过一个关于将字符串转换成小写的类似问题

我完全理解这是如何工作的，但我自己的尝试失败了

下面是我当前调试块的设置示例

#Debug block - Used to toggle the display of variable data throughout the game for debug purposes.
def debug():
    print("Would you like to play in Debug/Developer Mode?")
    while True:
        global egg
        choice = input()
        if choice == "yes":
            devdebug = 1
            break
        elif choice == "Yes":
            devdebug = 1
            break
        elif choice == "no":
            devdebug = 0
            break
        elif choice == "No":
            devdebug = 0
            break
        elif choice == "bunny":
            print("Easter is Here!")
            egg = 1
            break
        else:
            print("Yes or No?")
 #

因此，我预先编写了它，以便使用不同的大写字母。但是，我希望每个单词只使用一个

if

语句，而不是使用两个来表示大小写。我确实有一个想法，使用另一个块来确定真或假状态，看起来是这样的

def debugstate():
    while True:
        global devstate
        choice = input()
        if choice == "Yes":
            devstate = True
            break
        elif choice == "yes":
            devstate = True
            break
        elif choice == "No":
            devstate = False
            break
#Etc Etc Etc

但是使用这个代码块只需要将我已有的代码行移到其他地方。我知道我可以设置它，如果它不是“Yes”，那么else可以自动将devstate设置为0，但我更喜欢一个更受控制的环境。我不想意外地键入带有空格的“yes”并关闭devmode

回到问题上来

我该怎么做才能做到以下几点

def debug():
    print("Debug Mode?")
    while True:
        global egg
        choice = input()
        if choice == "yes" or "Yes":
            devdebug = 1
            break
        elif choice == "no" or "No":
            devdebug = 0
            break
        elif choice == "egg":
            devdebug = 0
            egg = 1
            print("Easter is Here")
            break
        else:
            print("Yes or No?")
#

上面的代码可能不是最好的例子，但当我说每个单词只需要一个

if

语句时，它至少帮助我理解了我的观点。（另外，我希望我没有在这里解决我自己的问题xD。）

那么，我该怎么做呢

（另外，我之所以选择这里而不是Python论坛，是因为我更喜欢以自己的方式提问，而不是试图从一个对其他人来说措辞不同的问题中拼凑出答案。）

使用.lower（）是最好的选择

choice = input()
choice = choice.lower()
if choice == 'yes':
    dev_debug = 1
    break

或者使用“in”

choice = input()
if choice in ('yes', 'Yes'):
    dev_debug = 1
    break

---

您可以在某个变量中输入小写值，并在不关心大小写的情况下使用该值而不是原始的

choice

，在大小写重要的情况下，您仍然可以使用

choice

：

def debug():
    print("Debug Mode?")
    while True:
        global egg
        choice = input()
        lowchoice = choice.lower()
        if lowchoice == "yes":
            devdebug = 1
            break
        elif lowchoice == "no":
            devdebug = 0
            break
        elif choice == "egg":
            devdebug = 0
            egg = 1
            print("Easter is Here")
            break
        else:
            print("Yes or No?")

---

一个词的答案：string.lower（）

要找出类/对象可用的变量/方法，只需使用dir（object/class/method（））

例如

a="foo"
type(a)
<type 'str'>
dir(a)
['__add__', '__class__', '__contains__', '__delattr__', '__doc__', '__eq__', '__format__', '__ge__', '__getattribute__', '__getitem__', '__getnewargs__', '__getslice__', '__gt__', '__hash__', '__init__', '__le__', '__len__', '__lt__', '__mod__', '__mul__', '__ne__', '__new__', '__reduce__', '__reduce_ex__', '__repr__', '__rmod__', '__rmul__', '__setattr__', '__sizeof__', '__str__', '__subclasshook__', '_formatter_field_name_split', '_formatter_parser', 'capitalize', 'center', 'count', 'decode', 'encode', 'endswith', 'expandtabs', 'find', 'format', 'index', 'isalnum', 'isalpha', 'isdigit', 'islower', 'isspace', 'istitle', 'isupper', 'join', 'ljust', 'lower', 'lstrip', 'partition', 'replace', 'rfind', 'rindex', 'rjust', 'rpartition', 'rsplit', 'rstrip', 'split', 'splitlines', 'startswith', 'strip', 'swapcase', 'title', 'translate', 'upper', 'zfill']

a=“foo”
类型（a）
处长（a）
“UUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUU"乐","乐","乐","乐","乐","乐","乐","乐","乐","乐,"乐","乐,"乐,"乐,","乐,","乐,"乐,,"乐,,"乐,34etattr_uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu，'rfind'，'rindex'，'rjust'，'rpartition'，'rsplit'，'rstrip'，'splitlines'，'startswith'，'strip'，'swapcase'，'title'，'translate'，'upper'，'zfill']

“我理解这是如何完美工作的，但我自己的尝试失败了”。我很想看看您试图使用

.lower

的代码。只要使用if choice.lower（）=“yes”就可以了done@Kevin让我困惑的是，放低了。“如何在python中将字符串转换为小写”对我来说，并没有向我大声说出我将把它放在哪里。lower@Wooble我看了那个问题，它对我没有任何帮助。@GameWylder你看不到你的

选择==“yes”或“yes”

条件实际上是

（选择==“yes”）或（“yes”）

-其中

是

part的评估结果总是

True

——在阅读了一个问题并给出了解决方案，解释了为什么这不是编写所需内容的方法之后？我尝试了第一个示例，它非常有效！感谢第二个例子，这肯定是我将来会用到的。再次感谢您或显示正确的设置。@GameWylder第二个示例与Wooble链接到您的问题的公认解决方案完全相同。