使用python从间接图到有向图

我想使用python将间接图转换为有向图。这是我的代码。我应该更改什么以获得有向图

我正在从graph.txt加载以下邻接矩阵（没有表示列标题或行名称的字母）：

当前代码：

import pandas as pd
import numpy as np
import networkx as nx  # version 2.2
import matplotlib.pyplot as plt
import re

f = np.loadtxt ('graph.txt')
ad=[]
for x in f:
    ad.append(x)
print(ad)
df = pd.DataFrame(ad, columns = ['A','B','C','D','E'], index = ['A','B','C','D','E'])
G = nx.from_pandas_adjacency(df)
pos = nx.circular_layout(G)
nx.draw(G, pos, with_labels=True, bbox = dict(fc="lightgreen", ec="black", boxstyle="circle", lw=3),
    width=2, arrowsize=30)
nx.draw_networkx_edge_labels(G, pos, edge_labels = nx.get_edge_attributes(G, 'weight'))
plt.show()

---

如何确定每条边的方向？根据关联矩阵：`A，B，C，D，E A1，1,0，1，0 B 0，-1,0,1，-1 C-1,0，-1,1,0 D 0,1,0,0,0 E-1,1,1,1，-1`，边必须从直线指向直线column@farahlana请在您的问题中添加更多信息。

graph.txt

的内容是什么？

import pandas as pd
import numpy as np
import networkx as nx  # version 2.2
import matplotlib.pyplot as plt
import re

f = np.loadtxt ('graph.txt')
ad=[]
for x in f:
    ad.append(x)
print(ad)
df = pd.DataFrame(ad, columns = ['A','B','C','D','E'], index = ['A','B','C','D','E'])
G = nx.from_pandas_adjacency(df)
pos = nx.circular_layout(G)
nx.draw(G, pos, with_labels=True, bbox = dict(fc="lightgreen", ec="black", boxstyle="circle", lw=3),
    width=2, arrowsize=30)
nx.draw_networkx_edge_labels(G, pos, edge_labels = nx.get_edge_attributes(G, 'weight'))
plt.show()