Python 使用pprint并跳过类型名称

我想使用

pprint

打印一些复杂的列表，请参见下面的示例：

>>> x = [OrderedDict([(u'D-ID', u'clci-2'), (u'R', u'1691')]), OrderedDict([(u'D-ID', u'dallas-pcc-1'), (u'R', u'5498')]), OrderedDict([(u'D-ID', u'gx-1'), (u'R', u'2275')]), OrderedDict([(u'D-ID', u'gx-2'), (u'R', u'0')]), OrderedDict([(u'D-ID', u'ocs-1'), (u'R', u'31735')]), OrderedDict([(u'D-ID', u'ocs-2'), (u'R', u'0')]), OrderedDict([(u'D-ID', u'pcc-gx-1'), (u'R', u'46351')]), OrderedDict([(u'D-ID', u'rgx-1'), (u'R', u'907')]), OrderedDict([(u'D-ID', u'rgx-2'), (u'R', u'1010')]), OrderedDict([(u'D-ID', u'rocs-1'), (u'R', u'915')]), OrderedDict([(u'D-ID', u'rocs-2'), (u'R', u'1033')])]
>>> pprint.pprint(x)
[OrderedDict([(u'D-ID', u'clci-2'), (u'R', u'1691')]),
 OrderedDict([(u'D-ID', u'dallas-pcc-1'), (u'R', u'5498')]),
 OrderedDict([(u'D-ID', u'gx-1'), (u'R', u'2275')]),
 OrderedDict([(u'D-ID', u'gx-2'), (u'R', u'0')]),
 OrderedDict([(u'D-ID', u'ocs-1'), (u'R', u'31735')]),
 OrderedDict([(u'D-ID', u'ocs-2'), (u'R', u'0')]),
 OrderedDict([(u'D-ID', u'pcc-gx-1'), (u'R', u'46351')]),
 OrderedDict([(u'D-ID', u'rgx-1'), (u'R', u'907')]),
 OrderedDict([(u'D-ID', u'rgx-2'), (u'R', u'1010')]),
 OrderedDict([(u'D-ID', u'rocs-1'), (u'R', u'915')]),
 OrderedDict([(u'D-ID', u'rocs-2'), (u'R', u'1033')])]

这很好，只是我想删除所有类型名（

orderedict&u

）和所有不必要的

[]

）可以使用pprint吗？

>>> import pprint
>>> from collections import OrderedDict
>>> x = [OrderedDict([(u'D-ID', u'clci-2'), (u'R', u'1691')]), OrderedDict([(u'D-ID', u'dallas-pcc-1'), (u'R', u'5498')]), OrderedDict([(u'D-ID', u'gx-1'), (u'R', u'2275')]), OrderedDict([(u'D-ID', u'gx-2'), (u'R', u'0')]), OrderedDict([(u'D-ID', u'ocs-1'), (u'R', u'31735')]), OrderedDict([(u'D-ID', u'ocs-2'), (u'R', u'0')]), OrderedDict([(u'D-ID', u'pcc-gx-1'), (u'R', u'46351')]), OrderedDict([(u'D-ID', u'rgx-1'), (u'R', u'907')]), OrderedDict([(u'D-ID', u'rgx-2'), (u'R', u'1010')]), OrderedDict([(u'D-ID', u'rocs-1'), (u'R', u'915')]), OrderedDict([(u'D-ID', u'rocs-2'), (u'R', u'1033')])]
>>> print pprint.pformat(x).replace("OrderedDict([", "(") \
                           .replace("u'", "'") \
                           .replace("])", ")")

[(('D-ID', 'clci-2'), ('R', '1691')),
 (('D-ID', 'dallas-pcc-1'), ('R', '5498')),
 (('D-ID', 'gx-1'), ('R', '2275')),
 (('D-ID', 'gx-2'), ('R', '0')),
 (('D-ID', 'ocs-1'), ('R', '31735')),
 (('D-ID', 'ocs-2'), ('R', '0')),
 (('D-ID', 'pcc-gx-1'), ('R', '46351')),
 (('D-ID', 'rgx-1'), ('R', '907')),
 (('D-ID', 'rgx-2'), ('R', '1010')),
 (('D-ID', 'rocs-1'), ('R', '915')),
 (('D-ID', 'rocs-2'), ('R', '1033'))]

---

根据您的需要调整

replace

s，我认为这看起来足够干净您需要创建自己的子类，并重写

.format（）

方法：

from pprint import PrettyPrinter, _recursion

class MyPrettyPrinter(PrettyPrinter):
    def format(self, object, context, maxlevels, level):
        if isinstance(object, OrderedDict):
            if not object:
                return "()", True, False

            objid = id(object)
            if maxlevels and level >= maxlevels:
                return "(...)", False, objid in context
            if objid in context:
                return _recursion(object), False, True
            context[objid] = 1
            readable = True
            recursive = False
            components = []
            append = components.append
            level += 1
            selfformat = self.format
            for k, v in sorted(object.items()):
                krepr, kreadable, krecur = selfformat(k, context, maxlevels, level)
                vrepr, vreadable, vrecur = selfformat(v, context, maxlevels, level)
                append('({}, {})'.format(krepr, vrepr))
                readable = readable and kreadable and vreadable
                if krecur or vrecur:
                    recursive = True
            del context[objid]
            return '({})'.format(', '.join(components)), readable, recursive

        formatted, readable, recursion = PrettyPrinter.format(self, object, context, maxlevels, level)
        if isinstance(object, unicode):
            formatted = formatted.lstrip('u')

        return formatted, readable, recursion

我们让基类完成大部分工作，只显式地格式化

OrderedDict

；它有一个自定义的

\uuu repr\uuu

，这意味着原始的

pprint

实现只是使用它，而不是在它上面递归

然后使用此类，而不是直接调用

pprint.pprint（）

：

这将产生：

>>> mypprint = MyPrettyPrinter()
>>> mypprint.pprint(x)
[(('D-ID', 'clci-2'), ('R', '1691')),
 (('D-ID', 'dallas-pcc-1'), ('R', '5498')),
 (('D-ID', 'gx-1'), ('R', '2275')),
 (('D-ID', 'gx-2'), ('R', '0')),
 (('D-ID', 'ocs-1'), ('R', '31735')),
 (('D-ID', 'ocs-2'), ('R', '0')),
 (('D-ID', 'pcc-gx-1'), ('R', '46351')),
 (('D-ID', 'rgx-1'), ('R', '907')),
 (('D-ID', 'rgx-2'), ('R', '1010')),
 (('D-ID', 'rocs-1'), ('R', '915')),
 (('D-ID', 'rocs-2'), ('R', '1033'))]

---

如果只是为了打印一些

dict

和

list

内容（或从它们继承的类中的内容），最好使用其他序列化，例如JSON:

import json
print json.dumps(obj)

---

为什么需要这样做？@jamylak我只需要打印上面这样的数据结构，跳过类型和[]是减小输出的好方法！怎么样

json.dumps

？@Boldewyn更好的主意，像这个主意一样提交itI，但我认为这不会拾取“内部”unicode字符串，如您的输出所示。@DSM:Urm，它不会递归。诅咒，所以我们需要递归自己，更新。@DSM:Better；由于自定义的

\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu。
import json
print json.dumps(obj)