Python PyQt5 QThread将变量传递给main
我正在尝试制作一个GUI,它将与串行设备交互 到目前为止,我已经成功地制作了一个非常简单的GUI,可以打开和关闭串行连接 下面是我的代码:Python PyQt5 QThread将变量传递给main,python,multithreading,Python,Multithreading,我正在尝试制作一个GUI,它将与串行设备交互 到目前为止,我已经成功地制作了一个非常简单的GUI,可以打开和关闭串行连接 下面是我的代码: import sys from PyQt5.QtCore import * from PyQt5.QtWidgets import QMainWindow, QApplication, QWidget, QMessageBox, QAction, qApp, QPushButton from PyQt5.QtGui import QIcon
import sys
from PyQt5.QtCore import *
from PyQt5.QtWidgets import QMainWindow, QApplication, QWidget, QMessageBox, QAction, qApp, QPushButton
from PyQt5.QtGui import QIcon
import serial
ser = serial.Serial()
ser.baudrate = 115200
ser.port = 2
class MainUI(QMainWindow):
def __init__(self):
super().__init__()
self.initUI()
self.workerThread = SerialRead()
self.connect(self.workerThread, QtCore.SIGNAL("mysignal(QString)"),self.on_change, QtCore.Qt.QueuedConnection)
def initUI(self):
btn1 = QPushButton('Open Serial', self)
btn1.clicked.connect(self.openSerial)
btn1.resize(btn1.sizeHint())
btn1.move(50,50)
btn2 = QPushButton('Close Serial', self)
btn2.clicked.connect(self.closeSerial)
btn2.resize(btn2.sizeHint())
btn2.move(50,100)
exitAction = QAction(QIcon('exit.png'), '&Exit', self)
exitAction.setShortcut('Alt+F4')
exitAction.setStatusTip('Exit application')
exitAction.triggered.connect(self.closeEvent)
self.statusBar()
menubar = self.menuBar()
fileMenu = menubar.addMenu('&File')
fileMenu.addAction(exitAction)
self.statusBar().showMessage('Ready')
self.setGeometry(300,300,250,150)
self.setWindowTitle('Motor Driver')
self.show()
def openSerial(self):
ser.open()
self.workerThread.start()
def closeSerial(self):
ser.close()
self.workerThread.terminate()
def closeEvent(self, event):
reply = QMessageBox.question(self, 'Message', "Are you sure you want to quit?", QMessageBox.Yes | QMessageBox.No, QMessageBox.No)
if reply == QMessageBox.Yes:
event.accept()
else:
event.ignore()
class SerialRead(QThread):
def __init__(self):
super().__init__()
self.data = []
def run(self):
while True:
x = ser.readline()
# if x != b'\n':
# self.data.append(str(x))
# else:
self.emit(QtCore.SIGNAL("mysignal(Qstring)"), (x.decode("utf-8")))
# self.data = []
if __name__ == '__main__':
app = QApplication(sys.argv)
main = MainUI()
sys.exit(app.exec_())
我的问题是如何将变量从serialRead线程传递到MainUI?
正如您在我的代码中所看到的,我已经尝试了我可以在网上找到的解决方案,这是通过使用:
self.connect(self.workerThread, QtCore.SIGNAL("mysignal(QString)"),self.on_change, QtCore.Qt.QueuedConnection)
self.emit(QtCore.SIGNAL("mysignal(Qstring)"), (x.decode("utf-8")))
在我的MainUI类上,并通过使用:
self.connect(self.workerThread, QtCore.SIGNAL("mysignal(QString)"),self.on_change, QtCore.Qt.QueuedConnection)
self.emit(QtCore.SIGNAL("mysignal(Qstring)"), (x.decode("utf-8")))
在我的线程上
但是,这给了我一个错误:
“MainUI”对象没有属性“connect”
那么,我应该如何将变量从线程传递到MainUI呢
自从我上一次接触python已经快2年了,大约2天前我才开始这个项目,但是我还有什么可以改进我的代码的吗?我是否有任何细微或明显的错误?在PyQt5上,您必须使用