Python-有没有一种方法可以将函数放入函数中而不获取；类型错误：'；int'；对象不可调用"；？
我正在做一个多人掷骰子游戏，你可以根据你掷的骰子得到分数。我试图把一个函数放在一个函数中，但是由于typeerror，这不起作用 我在网上搜索了如何减少函数之间的交互，试图从另一个函数中删除一个函数，但没有找到答案。我也问过我的同学和老师，但他们也不知道Python-有没有一种方法可以将函数放入函数中而不获取；类型错误：'；int'；对象不可调用"；？,python,python-3.x,function,module,Python,Python 3.x,Function,Module,我正在做一个多人掷骰子游戏，你可以根据你掷的骰子得到分数。我试图把一个函数放在一个函数中，但是由于typeerror，这不起作用 我在网上搜索了如何减少函数之间的交互，试图从另一个函数中删除一个函数，但没有找到答案。我也问过我的同学和老师，但他们也不知道 import random playerPoints = [] minPlayers = 2 players = 0 maxscore = 100 amountOfDice = 2 gameRound = 0 toRoll = "" die1
import random
playerPoints = []
minPlayers = 2
players = 0
maxscore = 100
amountOfDice = 2
gameRound = 0
toRoll = ""
die1 = random.randint(1, 6)
die2 = random.randint(1, 6)
def setPlayers():
while True:
players = input("How many players are playing?\n")
if players.isdigit():
players = int(players)
if minPlayers <= players:
for i in range(players):
playerPoints.append(0)
return players
def diceroll(player, amountOfDice, die1, die2):
throw = 0
print("Player {0}s turn:".format(player + 1))
for i in range(amountOfDice):
roll = 0
while roll != toRoll:
roll = input("Press enter to roll both dice")
if roll == toRoll:
print("Player {0} has thrown {1} and {2}".format(player + 1, i + 1, die1, die2))
break
points()
def cont():
cont = input("Would you like to continue or stop? Press [C] to continue or press [S] to stop.")
if cont == "c":
points()
elif cont == "s":
print("You have successfully cashed in " + str(points) + " points. Well done!")
playerPoints[players] += points
playerPoints[player] += throw
print("Player {0}s score is now: {1}".format(player + 1, playerPoints[player]))
return throw
def checkWin(maxscore):
for player in range(players):
if (playerPoints[player] >= maxscore):
print("Player {0} wins!".format(player + 1))
return True
return False
def points():
while die1 != 1 or die2 != 1 and cont == "c":
for i in playerPoints:
global points
points = 0
if die1 == 1 and die2 == 1:
print("That means you store " + str(double1) + " points.")
points += double1
cont()
elif die1 == die2:
print("That means you store " + str((die1 + die2)*2) + " points.")
points += (die1 + die2)*2
cont()
elif die1 != die2:
print("That means you store " + str(die1 + die2) + " points.")
points += die1 + die2
cont()
elif die1 == 1 or die2 == 2:
print("Unlucky! You have rolled " + str(die1) + " and " + str(die2) + ". Since you rolled a 1, your turn has ended. You have lost all stored points so far, and you lose " + str(die1 + die2) + " points.")
points -= (die1 + die2)
if __name__ == "__main__":
players = setPlayers()
while True:
gameRound += 1
print("Round: {0}".format(gameRound))
for i in range(players):
diceroll(i, amountOfDice, die1, die2)
if (checkWin(maxscore)):
break
def players(numberOfPlayers):
numberOfPlayers = 0
while numberOfPlayers not in (str(i) for i in range (minPlayers,maxPlayers)):
numberOfPlayers = int(numberOfPlayers)
for i in range(numberOfPlayers):
playerPoints["score{}".format(i+1)] = 0
return numberOfPlayers
随机导入
playerPoints=[]
minPlayers=2
玩家=0
maxscore=100
amountOfDice=2
gameRound=0
toRoll=“”
die1=random.randint（1,6）
die2=random.randint（1,6）
def setPlayers（）：
尽管如此：
玩家=输入（“有多少玩家在玩？\n”）
if players.isdigit（）：
玩家=int（玩家）
如果minPlayers=maxscore）：
打印（“玩家{0}获胜！”。格式（玩家+1））
返回真值
返回错误
def points（）：
而死亡1！=1或2！=1和cont==“c”：
对于我在playerPoints：
全局点
分数=0
如果die1==1和die2==1：
打印（“这意味着您存储“+str（double1）+”点。”）
点数+=双1
续（
elif die1==die2：
打印（“这意味着您存储”+str（（die1+die2）*2）+“点数”。）
点数+=（第1个+第2个）*2
续（
伊里夫·迪厄第二条：
打印（“这意味着您存储“+str（die1+die2）+”点数。”）
点数+=die1+die2
续（
elif die1==1或die2==2：
打印（“不幸！你掷了“+str（die1）+”和“+str（die2）+”。自从你掷了1之后，你的回合结束。到目前为止，你已经失去了所有存储的点数，并且失去了“+str（die1+die2）+”点数。”）
点-=（第1个点+第2个点）
如果名称=“\uuuuu main\uuuuuuuu”：
players=setPlayers（）
尽管如此：
gameRound+=1
打印（“回合：{0}”。格式（游戏回合））
对于范围内的i（玩家）：
骰子卷（i，数量，骰子1，骰子2）
如果（checkWin（maxscore））：
打破
def播放器（播放器数量）：
玩家数量=0
而numberOfPlayers不在（str（i）代表范围内的i（minPlayers，maxPlayers））：
numberOfPlayers=int（numberOfPlayers）
对于范围内的i（玩家数量）：
playerPoints[“score{}”.format（i+1）]=0
返回人数
玩家=2 通过执行playerPoints[player]，您试图访问不存在的第三个元素。列表索引从0开始
您可以执行playerPoints[player-1]当您按c键时的第一个错误是由于相同的变量和函数名“points”引起的。第二个错误是由于列表的索引不足而导致的，可以通过将索引减去1来修复 这是一个固定的代码
import random
playerPoints = []
minPlayers = 2
players = 0
maxscore = 100
amountOfDice = 2
gameRound = 0
toRoll = ""
die1 = random.randint(1, 6)
die2 = random.randint(1, 6)
def setPlayers():
while True:
players = input("How many players are playing?\n")
if players.isdigit():
players = int(players)
if minPlayers <= players:
for i in range(players):
playerPoints.append(0)
return players
def diceroll(player, amountOfDice, die1, die2):
throw = 0
print("Player {0}s turn:".format(player + 1))
for i in range(amountOfDice):
roll = 0
while roll != toRoll:
roll = input("Press enter to roll both dice")
if roll == toRoll:
print("Player {0} has thrown {1} and {2}".format(player + 1, i + 1, die1, die2))
break
func_points()
def cont():
cont = input("Would you like to continue or stop? Press [C] to continue or press [S] to stop.")
if cont == "c":
func_points()
elif cont == "s":
print("You have successfully cashed in " + str(points) + " points. Well done!")
print (playerPoints, players)
playerPoints[players - 1] += points
playerPoints[players - 1] += throw
print("Player {0}s score is now: {1}".format(player + 1, playerPoints[player]))
return throw
def checkWin(maxscore):
for player in range(players):
if (playerPoints[player] >= maxscore):
print("Player {0} wins!".format(player + 1))
return True
return False
def func_points():
while die1 != 1 or die2 != 1 and cont == "c":
for i in playerPoints:
global points
points = 0
if die1 == 1 and die2 == 1:
print("That means you store " + str(double1) + " points.")
points += double1
cont()
elif die1 == die2:
print("That means you store " + str((die1 + die2)*2) + " points.")
points += (die1 + die2)*2
cont()
elif die1 != die2:
print("That means you store " + str(die1 + die2) + " points.")
points += die1 + die2
cont()
elif die1 == 1 or die2 == 2:
print("Unlucky! You have rolled " + str(die1) + " and " + str(die2) + ". Since you rolled a 1, your turn has ended. You have lost all stored points so far, and you lose " + str(die1 + die2) + " points.")
points -= (die1 + die2)
if __name__ == "__main__":
players = setPlayers()
while True:
gameRound += 1
print("Round: {0}".format(gameRound))
for i in range(players):
diceroll(i, amountOfDice, die1, die2)
if (checkWin(maxscore)):
break
def players(numberOfPlayers):
numberOfPlayers = 0
while numberOfPlayers not in (str(i) for i in range (minPlayers,maxPlayers)):
numberOfPlayers = int(numberOfPlayers)
for i in range(numberOfPlayers):
playerPoints["score{}".format(i+1)] = 0
return numberOfPlayers
随机导入
playerPoints=[]
minPlayers=2
玩家=0
maxscore=100
amountOfDice=2
gameRound=0
toRoll=“”
die1=random.randint（1,6）
die2=random.randint（1,6）
def setPlayers（）：
尽管如此：
玩家=输入（“有多少玩家在玩？\n”）
if players.isdigit（）：
玩家=int（玩家）
如果minPlayers=maxscore）：
打印（“玩家{0}获胜！”。格式（玩家+1））
返回真值
返回错误
def func_points（）：
而死亡1！=1或2！=1和cont==“c”：
对于我在playerPoints：
全局点
分数=0
如果die1==1和die2==1：
打印（“这意味着您存储“+str（double1）+”点。”）
点数+=双1
续（
elif die1==die2：
打印（“这意味着您存储”+str（（die1+die2）*2）+“点数”。）
点数+=（第1个+第2个）*2
续（
伊里夫·迪厄第二条：
打印（“这意味着您存储“+str（die1+die2）+”点数。”）
点数+=die1+die2
续（
elif die1==1或die2==2：
打印（“不幸！你掷了“+str（die1）+”和“+str（die2）+”。自从你掷了1之后，你的回合结束。到目前为止，你已经失去了所有存储的点数，并且失去了“+str（die1+die2）+”点数。”）
点-=（第1个点+第2个点）
如果名称=“\uuuuu main\uuuuuuuu”：
players=setPlayers（）
尽管如此：
gameRound+=1
打印（“回合：{0}”。格式（游戏回合））
对于范围内的i（玩家）：
骰子卷（i，数量，骰子1，骰子2）
如果（checkWin（maxscore））：
打破
def播放器（播放器数量）：
玩家数量=0
而numberOfPlayers不在（str（i）代表范围内的i（minPlayers，maxPlayers））：
numberOfPlayers=int（numberOfPlayers）
对于范围内的i（玩家数量）：
playerPoints[“score{}”.format（i+1）]=0
返回人数
为了便于将来参考，最好的编程实践是给出适当的变量和函数名，以避免混淆和更糟糕的bug。考虑为函数和变量使用单独的名称。使用相同的名称会产生阴影并损害可读性。是的，很抱歉代码太混乱。我只是没有独创性啊哈，但这不是问题所在，即使是一个简单的后缀，如
\u var\u func