用python打印彩色文本

我有一些文字，特别强调了一些单词

from termcolor import colored
text='left foot right foot left foot right. Feet in the day, feet at night.'
l1=['foot','feet']
result = " ".join(colored(t,'white','on_red') if t in l1 else t for t in text.lower().split())
print(result)

我对pyhthon比较陌生，我想知道是否有办法创建一个视觉/情节来显示句子并将其打印到屏幕上。我只想打印几个句子。如果我能将整个故事（10万字）打印到文档文件中，那就太好了

我想到了画突出显示的句子，想到了matplotlib，但我认为这行不通。还有其他的视觉效果吗

如果可能，我想打印并保存png等：

---

非常有趣的问题。我为您提供了一个针对几个句子的案例的解决方案，但是如果您想为整个文档创建这个，我建议您使用任何PDF编写器

import matplotlib.pyplot as plt

def color_code():
    text='left foot right foot left foot right. Feet in the day, feet at night.'
    text_split = text.split(" ")
    l1=['foot','feet']

    # Pixels where you want to start first word
    start_x = 20
    start_y = 450

    # Decide what is the last pixel for writing words in one line
    end = 600

    # Whitespace in pixels
    whitespace = 8

    # Create figure
    figure = plt.figure()

    # From renderer we can get textbox width in pixels
    rend = figure.canvas.get_renderer()
    for word in (text_split):
        # Text box parameters and colors
        bbox = dict(boxstyle="round,pad=0.3", fc="red", ec="b", lw=2)

        # Check if word contains "foot", "feet", "foot." or "feet." or caps locked.
        # Depending what you are trying to achieve.
        if (word in l1 or word.replace('.','') in l1 or word.lower() in l1):
            txt = plt.text(start_x, start_y, word, color="black", bbox=bbox,transform=None)
        else:
            txt = plt.text(start_x, start_y, word, transform=None)
        # Textbox width
        bb = txt.get_window_extent(renderer=rend)

        # Calculate where next word should be written
        start_x = bb.width + start_x + whitespace

        # Next line if end parameter in pixels have been crossed
        if start_x >= end:
            start_x = 20
            start_y -= 40

    # Skip plotting axis
    plt.axis("off")
    # Save and plot figure
    plt.savefig("plot.png")
    plt.show()


color_code()

字符串较长的结果应如下所示：

---

非常有趣的问题。我为您提供了一个针对几个句子的案例的解决方案，但是如果您想为整个文档创建这个，我建议您使用任何PDF编写器

import matplotlib.pyplot as plt

def color_code():
    text='left foot right foot left foot right. Feet in the day, feet at night.'
    text_split = text.split(" ")
    l1=['foot','feet']

    # Pixels where you want to start first word
    start_x = 20
    start_y = 450

    # Decide what is the last pixel for writing words in one line
    end = 600

    # Whitespace in pixels
    whitespace = 8

    # Create figure
    figure = plt.figure()

    # From renderer we can get textbox width in pixels
    rend = figure.canvas.get_renderer()
    for word in (text_split):
        # Text box parameters and colors
        bbox = dict(boxstyle="round,pad=0.3", fc="red", ec="b", lw=2)

        # Check if word contains "foot", "feet", "foot." or "feet." or caps locked.
        # Depending what you are trying to achieve.
        if (word in l1 or word.replace('.','') in l1 or word.lower() in l1):
            txt = plt.text(start_x, start_y, word, color="black", bbox=bbox,transform=None)
        else:
            txt = plt.text(start_x, start_y, word, transform=None)
        # Textbox width
        bb = txt.get_window_extent(renderer=rend)

        # Calculate where next word should be written
        start_x = bb.width + start_x + whitespace

        # Next line if end parameter in pixels have been crossed
        if start_x >= end:
            start_x = 20
            start_y -= 40

    # Skip plotting axis
    plt.axis("off")
    # Save and plot figure
    plt.savefig("plot.png")
    plt.show()


color_code()

字符串较长的结果应如下所示：

---

使用相同的逻辑，将10万个文档写入doc或pdf实际上相当容易使用相同的逻辑，将10万个文档写入doc或pdf实际上相当容易