python骰子滚动重启脚本

我想自动重新启动我的脚本我有一个掷骰子脚本，我不想在每次掷骰之间手动重置脚本这是我的脚本

import random
from random import randrange
from random import randint
r = randint
min = 1
max = 6

rolls = int(float(input('how menny times do you want to roll:')))

for x in range(rolls):
    print ('Rolling the dices...')
    print ('The value is....')
    print (r(min, max))

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我尝试过几种方法，但没有一种有效

我不能100%确定您实际上想做什么，但我编写了一个程序，它将一次滚动2次，并将生成您想要滚动的滚动数量-使用递归（main从自身内部调用main）并不是最佳实践，但这并不是一个基本问题

*如果您使用的是Python 3+，请将原始输入替换为输入。我使用2.7，所以我使用原始输入

import time
import random

def roll_multiple():
#honestly this is all you need to do what you want to do, the rest just turns it into a game and allows multiple runs
    roll_number = int(raw_input("How Many Times Would You Like to Roll?\n"))
    for i in range(roll_number):
        print"You Rolled A ", random.randrange(1,6,1), " and a ", random.randrange(1,6,1)
#that's it! if you do these 3 lines, it will ask for how many times, and for each item in range of roll_number (whatever you input) it will run the print below and generate new numbers for each roll.

def main():
    print("Welcome to Craps 2.0")
    playing = raw_input("Press Enter to Roll or Q to quit")

    if playing == 'q':
        print("Thanks for Playing")
        time.sleep(2)
        quit()
    elif playing != 'q':
        roll_multiple()
        main()
main()

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你尝试过哪些方法，哪些方法不奏效？仅供参考，

'menny'！='许多“

。听起来你应该阅读

while循环

一个简单的

while循环

就可以了。谢谢我编辑了这个，使之与我的python版本一起使用，它工作得非常好。