Python 计算一个角色在电影剧本中说的话
在一些帮助下，我已经设法找出了所说的话。 现在，我正在寻找一个被选中的人说的文本。 这样我就可以输入MIA，并得到她在电影中说的每一句话 像这样：Python 计算一个角色在电影剧本中说的话,python,python-3.x,text,count,movie,Python,Python 3.x,Text,Count,Movie,在一些帮助下，我已经设法找出了所说的话。 现在，我正在寻找一个被选中的人说的文本。 这样我就可以输入MIA，并得到她在电影中说的每一句话 像这样： name = input("Enter name:") wordsspoken(script, name) name1 = input("Enter another name:") wordsspoken(script, name1) 所以我可以数一数后面的单词 这就是电影剧本的样子 An awkward beat. They pass a woo
name = input("Enter name:")
wordsspoken(script, name)
name1 = input("Enter another name:")
wordsspoken(script, name1)
An awkward beat. They pass a wooden SALOON -- where a WESTERN
is being shot. Extras in COWBOY costumes drink coffee on the
steps.
Revision 25.
MIA (CONT'D)
I love this stuff. Makes coming to work
easier.
SEBASTIAN
I know what you mean. I get breakfast
five miles out of the way just to sit
outside a jazz club.
MIA
Oh yeah?
SEBASTIAN
It was called Van Beek. The swing bands
played there. Count Basie. Chick Webb.
(then,)
It's a samba-tapas place now.
MIA
A what?
SEBASTIAN
Samba-tapas. It's... Exactly. The joke's on
history.
我会要求用户首先输入脚本中的所有名称。然后问他们想要这些单词的名字。我会逐字搜索文本，直到找到所需的名称，并将以下单词复制到变量中，直到找到与脚本中其他人匹配的名称。现在人们可以说出另一个角色的名字，但是如果你假设说的人的头衔都是大写的，或者在一行上，那么文本应该很容易过滤
for word in script:
if word == speaker and word.isupper(): # you may want to check that this is on its own line as well.
recording = True
elif word in character_names and word.isupper(): # you may want to check that this is on its own line as well.
recording = False
if recording:
spoken_text += word + " "
我会要求用户首先输入脚本中的所有名称。然后问他们想要这些单词的名字。我会逐字搜索文本，直到找到所需的名称，并将以下单词复制到变量中，直到找到与脚本中其他人匹配的名称。现在人们可以说出另一个角色的名字，但是如果你假设说的人的头衔都是大写的，或者在一行上，那么文本应该很容易过滤
for word in script:
if word == speaker and word.isupper(): # you may want to check that this is on its own line as well.
recording = True
elif word in character_names and word.isupper(): # you may want to check that this is on its own line as well.
recording = False
if recording:
spoken_text += word + " "
如果你只想通过一次脚本来计算你的计数（我想可能会很长），你可以只跟踪哪个角色在说话；设置类似于小型状态机的东西：
import re
from collections import Counter, defaultdict
words_spoken = defaultdict(Counter)
currently_speaking = 'Narrator'
for line in SCRIPT.split('\n'):
name = line.replace('(CONT\'D)', '').strip()
if re.match('^[A-Z]+$', name):
currently_speaking = name
else:
words_spoken[currently_speaking].update(line.split())
如果你只想通过一次脚本（我想可能会很长）来计算你的计数，你可以只跟踪哪个角色在说话；设置类似于小型状态机的东西：
import re
from collections import Counter, defaultdict
words_spoken = defaultdict(Counter)
currently_speaking = 'Narrator'
for line in SCRIPT.split('\n'):
name = line.replace('(CONT\'D)', '').strip()
if re.match('^[A-Z]+$', name):
currently_speaking = name
else:
words_spoken[currently_speaking].update(line.split())
我将概述如何生成一个dict，该dict可以为所有演讲者提供所说的字数，并提供一个近似于现有实现的dict
import re
def wordsspoken(script,name):
word_count = 0
for line in script.split('\n'):
if re.match('^[ ]{19}[^ ]{1,}.*', line): # name of speaker
speaker = line.split(' (')[0][19:]
if re.match('^[ ]{6}[^ ]{1,}.*', line): # dialogue line
if speaker == name:
word_count += len(line.split())
print(word_count)
def main():
name = input("Enter name:")
wordsspoken(script, name)
name1 = input("Enter another name:")
wordsspoken(script, name1)
{'JOHN DOE'：55}>>> word_count['MIA']
13
import re
def wordsspoken(script,name):
word_count = 0
for line in script.split('\n'):
if re.match('^[ ]{19}[^ ]{1,}.*', line): # name of speaker
speaker = line.split(' (')[0][19:]
if re.match('^[ ]{6}[^ ]{1,}.*', line): # dialogue line
if speaker == name:
word_count += len(line.split())
print(word_count)
def main():
name = input("Enter name:")
wordsspoken(script, name)
name1 = input("Enter another name:")
wordsspoken(script, name1)
我将概述如何生成一个dict，该dict可以为所有演讲者提供所说的单词数量，并提供一个近似于现有实现的dict
import re
def wordsspoken(script,name):
word_count = 0
for line in script.split('\n'):
if re.match('^[ ]{19}[^ ]{1,}.*', line): # name of speaker
speaker = line.split(' (')[0][19:]
if re.match('^[ ]{6}[^ ]{1,}.*', line): # dialogue line
if speaker == name:
word_count += len(line.split())
print(word_count)
def main():
name = input("Enter name:")
wordsspoken(script, name)
name1 = input("Enter another name:")
wordsspoken(script, name1)
{'JOHN DOE'：55}>>> word_count['MIA']
13
import re
def wordsspoken(script,name):
word_count = 0
for line in script.split('\n'):
if re.match('^[ ]{19}[^ ]{1,}.*', line): # name of speaker
speaker = line.split(' (')[0][19:]
if re.match('^[ ]{6}[^ ]{1,}.*', line): # dialogue line
if speaker == name:
word_count += len(line.split())
print(word_count)
def main():
name = input("Enter name:")
wordsspoken(script, name)
name1 = input("Enter another name:")
wordsspoken(script, name1)
上面有一些好主意。在Python2.x和3.x中，以下内容应该可以正常工作：
import codecs
from collections import defaultdict
speaker_words = defaultdict(str)
with codecs.open('script.txt', 'r', 'utf8') as f:
speaker = ''
for line in f.read().split('\n'):
# skip empty lines
if not line.split():
continue
# speakers have their names in all uppercase
first_word = line.split()[0]
if (len(first_word) > 1) and all([char.isupper() for char in first_word]):
# remove the (CONT'D) from a speaker string
speaker = line.split('(')[0].strip()
# check if this is a dialogue line
elif len(line) - len(line.lstrip()) == 6:
speaker_words[speaker] += line.strip() + ' '
# get a Python-version-agnostic input
try:
prompt = raw_input
except:
prompt = input
speaker = prompt('Enter name: ').strip().upper()
print(speaker_words[speaker])
Enter name: sebastian
I know what you mean. I get breakfast five miles out of the way just to sit outside a jazz club. It was called Van Beek. The swing bands played there. Count Basie. Chick Webb. It's a samba-tapas place now. Samba-tapas. It's... Exactly. The joke's on history.
上面有一些好主意。在Python2.x和3.x中，以下内容应该可以正常工作：
import codecs
from collections import defaultdict
speaker_words = defaultdict(str)
with codecs.open('script.txt', 'r', 'utf8') as f:
speaker = ''
for line in f.read().split('\n'):
# skip empty lines
if not line.split():
continue
# speakers have their names in all uppercase
first_word = line.split()[0]
if (len(first_word) > 1) and all([char.isupper() for char in first_word]):
# remove the (CONT'D) from a speaker string
speaker = line.split('(')[0].strip()
# check if this is a dialogue line
elif len(line) - len(line.lstrip()) == 6:
speaker_words[speaker] += line.strip() + ' '
# get a Python-version-agnostic input
try:
prompt = raw_input
except:
prompt = input
speaker = prompt('Enter name: ').strip().upper()
print(speaker_words[speaker])
Enter name: sebastian
I know what you mean. I get breakfast five miles out of the way just to sit outside a jazz club. It was called Van Beek. The swing bands played there. Count Basie. Chick Webb. It's a samba-tapas place now. Samba-tapas. It's... Exactly. The joke's on history.
这是一个粗略的算法，可能需要对不需要的东西进行细化，如（CONT'D）等。这是一个粗略的算法，可能需要对不需要的东西进行细化，如（CONT'D）等。在剧本创作中，
（CONT'D）行。替换语句以反映这一点。@唯一的问题似乎是dict.将每个单词显示一次。但我需要一个数字end@duhaimePinged在屏幕编写中，只需将<代码>设置<代码>换成<代码>计数器
中的<代码>初始化（调整帖子以反映这一点），其他<代码>（续）行。替换语句以反映这一点。@唯一的问题似乎是dict.将每个单词显示一次。但我需要一个数字end@duhaimepingedJust调出set
用于Counter
中的words\u speaked
初始化（只是调整了帖子以反映这一点）我发现这是一个错误：回溯（最近一次调用）：文件“/Users/*path*.py”，第19行，在wordsspoken（脚本，名称）中文件“/Users/*path*.py”，第13行，如果speaker==name:UnboundLocalError:local变量“speaker”在赋值之前被引用，你知道要更改什么吗？如果你给wordsspoken
一个脚本，在该脚本中，在引入演讲者之前，第一行对话被读取。例如，如果使用MIA（CONT'D）
之后的所有内容，而不是整个脚本。这段代码不解释没有说话人的对话，但您可以通过指定一个通用名称或抛出没有说话人的对话行来实现。我得到的错误是：回溯（最近一次调用）：File“/Users/*path*.py”，第19行，在wordsspoken（脚本，名称）文件“/Users/*path*.py”中，第13行，wordsspoken if speaker==name:UnboundLocalError:赋值前引用的局部变量“speaker”你知道要更改什么吗？如果你给wordsspoken
一个脚本，在该脚本中，在引入演讲者之前读取第一行对话，就会发生这种情况。例如，如果使用MIA（CONT'D）