Python 从lxml树中提取数据 序言:
遗憾的是,它不能完全工作,因此我无法从lxml树中提取我想要的数据。我对这个具体的案例并不特别感兴趣;我在寻找更一般的答案Python 从lxml树中提取数据 序言:,python,xpath,lxml,Python,Xpath,Lxml,遗憾的是,它不能完全工作,因此我无法从lxml树中提取我想要的数据。我对这个具体的案例并不特别感兴趣;我在寻找更一般的答案 import sys from PyQt4.QtGui import * from PyQt4.QtCore import * from PyQt4.QtWebKit import * from lxml import html class Render(QWebPage): def __init__(self, url): self
import sys
from PyQt4.QtGui import *
from PyQt4.QtCore import *
from PyQt4.QtWebKit import *
from lxml import html
class Render(QWebPage):
def __init__(self, url):
self.app = QApplication(sys.argv)
QWebPage.__init__(self)
self.loadFinished.connect(self._loadFinished)
self.mainFrame().load(QUrl(url))
self.app.exec_()
def _loadFinished(self, result):
self.frame = self.mainFrame()
self.app.quit()
url = 'http://pycoders.com/archive/'
#This does the magic.Loads everything
r = Render(url)
#result is a QString.
result = r.frame.toHtml()
#QString should be converted to string before processed by lxml
formatted_result = str(result.toAscii())
#Next build lxml tree from formatted_result
tree = html.fromstring(formatted_result)
《指南》继续做:
archive_links = tree.xpath('//divass="campaign"]/a/@href')
这会导致错误:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "src\lxml\lxml.etree.pyx", line 1587, in lxml.etree._Element.xpath (src\lxml\lxml.etree.c:59353)
File "src\lxml\xpath.pxi", line 307, in lxml.etree.XPathElementEvaluator.__call__ (src\lxml\lxml.etree.c:171227)
File "src\lxml\xpath.pxi", line 227, in lxml.etree._XPathEvaluatorBase._handle_result (src\lxml\lxml.etree.c:170184)
lxml.etree.XPathEvalError: Invalid expression
可能是打字错误。请尝试以下方法:
archive_links = tree.xpath('//div[class="campaign"]/a/@href')
或:
该语法更有意义,但遗憾的是,它为我返回了
archive\u links=[]
。@MitchellvanZuylen,这是因为您只请求初始页面源代码,而要获取链接,您需要等待JavaScript
执行完成根据指南,Render
类等待JS执行。我是否误解了指南,指南是否错了,或者您是否错过了渲染
类?@MitchellvanZuylen,或者可能我的假设是错的:)实际上,代码行应该是archive\u links=tree.xpath(//div[@class=“campaign”]/a/@href)
。注意@class
,而不仅仅是class
。
archive_links = tree.xpath('//div[class="campaign"]/a/@href')
archive_links = tree.xpath('//div[@class="campaign"]/a/@href')