python在每个子文件夹中创建一个文件

我需要帮助！ 我需要创建10个子目录：A1，A2，…，A10。每个子目录都包含一个名为position的文件，其中包含以下内容：

2.22222  0.44444  1.58810
5.77778  1.5556  0.41190

每个文件的结尾都包含一个对应于子目录的位置： 例如： 目录A1中的位置：

2.22222  0.44444  1.58810
5.77778  1.55556  0.41190
1.00000  1.00000  1.00000

目录A2中的位置包含

2.22222  0.44444  1.58810
5.77778  1.55556  0.41190
2.00000  2.00000  2.00000

类似于目录A3中的位置，包含：

2.22222  0.44444  1.58810
5.77778  1.55556  0.41190
3.00000  3.00000  3.00000

等等。我试图用python编写代码，但当出现错误时，它并没有很好地工作 IOError:[Errno 21]是一个目录：

import os
content += u"0.22222  0.44444  0.58810"
content += u"0.77778  0.55556  0.41190" 
num = 0
for i in range(0, 10)
   num = num + 1
   subdirectory = str("A")+str(num)
   os.mkdir (subdirectory)
   filename = str(position)
   for ip in open(filename):
   with open (os.path.join(subdirectory)) as ip:
   fp.write(content)
   for ip in open(filename):
      with open (os.path.join(subdirectory)) as ip:
          ft.write"{:.5f}  {:.5f}  {:.5f} ".format(num, num, num)

---

请帮我调试这个代码

您的第一个for循环需要在“for i in range（0，10）”位后加一个冒号

可能成为

for i in range (0, 10):
    num += 1

我想我能看到的唯一错误就是缺少冒号

num += 1 

---

做与您所做的完全相同的事情，这是一种很好的快速编码方式。你的缩进也不正确，所以如果你把它也整理出来，应该没问题。

它在我的机器上工作

import os
dir_path = os.path.dirname(os.path.realpath(__file__))
# print(dir_path)     #here, you will choose the working directory. currently, it is the same as your python file.
# for readibility, you can use multi-line string here.
content = '''
2.22222  0.44444  1.58810
5.77778  1.5556  0.41190
'''
for i in range(0, 10):
   foldername = dir_path+"\\"+'a'+str(i+1)
   os.makedirs(foldername)
   # use encoding 'utf-8' if you would like so.
   with open(foldername+"\\position.txt",'w',encoding='utf-8') as 
       innerfile:
       innerfile.write(content)
       innerfile.write('{:.5f}  {:.5f}  {:.5f}'.format(i+1,i+1,i+1))

---

pathlib可以更容易地考虑这一点，因为它可以将自己的路径名连接起来。如果目录不存在，此代码剪切将生成目录，并创建一个文件（如果不存在），并将

2.000002.000002.00000…

字符串附加到每个目录中

from pathlib import Path
dirnames = {'A01': 1, 'A02': 2, 'A03': 3, 'A10': 10}
basePath = Path('./foobar') # base path to work in
myFile = Path('file.txt') # name of each file to append to
repeats = 4 # number of times to repeat the appended value string
for name, value in dirnames.items():
    # Create the file    
    myName = Path(basePath/name)

    # Make the directories
    try:
        myName.mkdir()
    except FileExistsError:
        print('{} exists, skipping'.format(myName))

    # make the string that will be appended to each file
    myString = ''
    print(myFile)
    for i in range(0, repeats):
        myString = myString + ('{:.5f} '.format(value))
    myString + '\n'

    fileName = Path(myName/myFile) # set the file name 

    # write the string out to the file
    with fileName.open(mode='a') as dataOut:
        dataOut.write(myString)

---

你能修复缩进吗？还有，很多变量都没有实例化！

from pathlib import Path
dirnames = {'A01': 1, 'A02': 2, 'A03': 3, 'A10': 10}
basePath = Path('./foobar') # base path to work in
myFile = Path('file.txt') # name of each file to append to
repeats = 4 # number of times to repeat the appended value string
for name, value in dirnames.items():
    # Create the file    
    myName = Path(basePath/name)

    # Make the directories
    try:
        myName.mkdir()
    except FileExistsError:
        print('{} exists, skipping'.format(myName))

    # make the string that will be appended to each file
    myString = ''
    print(myFile)
    for i in range(0, repeats):
        myString = myString + ('{:.5f} '.format(value))
    myString + '\n'

    fileName = Path(myName/myFile) # set the file name 

    # write the string out to the file
    with fileName.open(mode='a') as dataOut:
        dataOut.write(myString)