Python 当它说：“我该怎么办？”；属性错误：'；功能'；对象没有属性'；追加'&引用；？

当我在做一个Codecademy挑战时，我遇到了一个问题，当我想检查我的答案时，出现了以下消息：

estimate\u insurance\u cost.append（（“Maria”，Maria\u insurance\u cost））AttributeError:“function”对象没有属性“append”

def estimate_insurance_cost(name, age, sex, bmi, num_of_children, smoker):
  estimated_cost = 250*age - 128*sex + 370*bmi + 425*num_of_children + 24000*smoker - 12500
  print(name + "'s Estimated Insurance Cost: " + str(estimated_cost) + " dollars.")
  return estimated_cost
 
# Estimate Maria's insurance cost
maria_insurance_cost = estimate_insurance_cost(name = "Maria", age = 31, sex = 0, bmi = 23.1, num_of_children = 1, smoker = 0)

# Estimate Rohan's insurance cost
rohan_insurance_cost = estimate_insurance_cost(name = 
"Rohan", age = 25, sex = 1, bmi = 28.5, num_of_children = 3, smoker = 0)

# Estimate Valentina's insurance cost
valentina_insurance_cost = estimate_insurance_cost(name = "Valentina", age = 53, sex = 0, bmi = 31.4, num_of_children = 0, smoker = 1)


names = ["Maria", "Rohan", "Valentina"]
insurance_costs = ["4150.0", "5320.0", "35210.0"]
insurance_data = zip(names, insurance_costs)
print(insurance_data)
insurance_data = list(zip(names, insurance_costs))
print(insurance_data)

estimate_insurance_cost.append(("Maria", maria_insurance_cost))
estimate_insurance_cost.append(("Rohan", rohan_insurance_cost))
estimate_insurance_cost.append(("Valentina", valentina_insurance_cost))
print(estimate_insurance_cost)

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看起来您正试图创建一个估计保险成本的列表（或者字典，也许？），但您给它起的名称与您的函数相同，并且除了函数之外，您还没有显式声明它

下面是如何使用以下信息创建一个名为

估算成本

的字典：

estimated_costs = {
    "Maria": maria_insurance_cost,
    "Rohan": rohan_insurance_cost,
    "Valentina": valentina_insurance_cost,
}

---

您的列表是

保险数据

，

估计保险成本

是您的职责谢谢您，兄弟！从一周前开始，感谢该社区的快速建议！