Python多线程工作负载崩溃 #/usr/bin/env python #-*-编码：utf-8-*- # #无标题3.py # #版权所有2015 Ognjen Galic # #这个程序是自由软件；您可以重新分发和/或修改它 #它是根据GNU通用公共许可证的条款发布的 自由软件基金会；许可证的第2版，或 #（由您选择）任何更高版本。 # #这个节目的发布是希望它会有用， #但无任何保证；甚至没有任何关于 #适销性或适合某一特定目的。见 #有关更多详细信息，请参阅GNU通用公共许可证。 # #您应该已经收到GNU通用公共许可证的副本 #与此同时,；如果没有，请写信给自由软件 波士顿基金会51楼富兰克林街第五楼 #MA 02110-1301，美国。 # # 导入命令 导入线程 从ui导入ui\u主窗口 从PyQt4导入QtGui、QtCore 从时间上导入睡眠 导入系统 类主窗口（QtGui.QMainWindow、Ui\u主窗口）： 定义初始化（自）： 超级（主窗口，自我）。\uuuu初始化 self.setupUi（self） def do_sudo（命令）： #使用命令执行任务（） def ui（）： app=QtGui.QApplication（sys.argv） ui.main窗口（） ui.show（） def main（）： ui=主窗口（） 对于范围（1100）内的i： ui.progressBar.setValue（i） 睡眠（1） 如果uuuu name uuuuuu='\uuuuuuu main\uuuuuuu'： threading.Thread（target=ui.start（）） threading.Thread（target=main）.start（）

这是为什么

我需要让UI在运行commands（）的同时进行刷新，并在更新UI的同时进行更新

为了测试它，我设置了一个小型for循环

---

但它会在运行时立即抛出和分段错误，代码为139。

尝试在创建线程后添加while True循环：

#!/usr/bin/env python
# -*- coding: utf-8 -*-
#
#  untitled3.py
#  
#  Copyright 2015 Ognjen Galic <gala@thinkpad>
#  
#  This program is free software; you can redistribute it and/or modify
#  it under the terms of the GNU General Public License as published by
#  the Free Software Foundation; either version 2 of the License, or
#  (at your option) any later version.
#  
#  This program is distributed in the hope that it will be useful,
#  but WITHOUT ANY WARRANTY; without even the implied warranty of
#  MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
#  GNU General Public License for more details.
#  
#  You should have received a copy of the GNU General Public License
#  along with this program; if not, write to the Free Software
#  Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston,
#  MA 02110-1301, USA.
#  
#  

import commands
import threading
from ui import Ui_main_window
from PyQt4 import QtGui, QtCore
from time import sleep
import sys

class MainWindow(QtGui.QMainWindow, Ui_main_window):
    def __init__(self):
        super(MainWindow, self).__init__()
        self.setupUi(self)

def do_sudo(command):
    # do stuffs with commands()

def ui():
    app = QtGui.QApplication(sys.argv)
    ui.MainWindow()
    ui.show()

def main():
    ui = MainWindow()
    for i in range(1,100):
            ui.progressBar.setValue(i)
            sleep(1)

if __name__ == '__main__':
    threading.Thread(target = ui).start()
    threading.Thread(target = main).start()

---

尝试在创建线程后添加while True循环：

#!/usr/bin/env python
# -*- coding: utf-8 -*-
#
#  untitled3.py
#  
#  Copyright 2015 Ognjen Galic <gala@thinkpad>
#  
#  This program is free software; you can redistribute it and/or modify
#  it under the terms of the GNU General Public License as published by
#  the Free Software Foundation; either version 2 of the License, or
#  (at your option) any later version.
#  
#  This program is distributed in the hope that it will be useful,
#  but WITHOUT ANY WARRANTY; without even the implied warranty of
#  MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
#  GNU General Public License for more details.
#  
#  You should have received a copy of the GNU General Public License
#  along with this program; if not, write to the Free Software
#  Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston,
#  MA 02110-1301, USA.
#  
#  

import commands
import threading
from ui import Ui_main_window
from PyQt4 import QtGui, QtCore
from time import sleep
import sys

class MainWindow(QtGui.QMainWindow, Ui_main_window):
    def __init__(self):
        super(MainWindow, self).__init__()
        self.setupUi(self)

def do_sudo(command):
    # do stuffs with commands()

def ui():
    app = QtGui.QApplication(sys.argv)
    ui.MainWindow()
    ui.show()

def main():
    ui = MainWindow()
    for i in range(1,100):
            ui.progressBar.setValue(i)
            sleep(1)

if __name__ == '__main__':
    threading.Thread(target = ui).start()
    threading.Thread(target = main).start()

---

启动线程后，程序不会等待线程运行。尝试在创建线程后添加一个while True:time.sleep（1.0）。成功了！多线程新手，不知道！发布我的投票答案！如果name='main'：threading.Thread（target=ui）.start（）sleep（1）threading.Thread（target=main）.start（）sleep（1）启动线程后，程序不会等待线程运行。尝试在创建线程后添加一个while True:time.sleep（1.0）。成功了！多线程新手，不知道！发布我的投票答案！如果name='main'：threading.Thread（target=ui）.start（）sleep（1）threading.Thread（target=main）.start（）sleep（1）