Python正则表达式在前面的子字符串匹配后获取子字符串
文本没有空格,所以我根本无法拆分并对字符串列表使用索引 我正在寻找的模式是:Python正则表达式在前面的子字符串匹配后获取子字符串,python,regex,Python,Regex,文本没有空格,所以我根本无法拆分并对字符串列表使用索引 我正在寻找的模式是: check= 它后面是一个数字和编码的querystring项(apachelogfile),并且在文件的每一行上出现两次。我想要的输出只提供以下内容check= 例如,行中的字符串如下所示: 11.249.222.103 - - [15/Aug/2016:13:17:56 -0600] "GET /next2/120005079807?check=37593467%2CCOB&check=37593378%2
check=
它后面是一个数字和编码的querystring项(apachelogfile),并且在文件的每一行上出现两次。我想要的输出只提供以下内容check=
例如,行中的字符串如下所示:
11.249.222.103 - - [15/Aug/2016:13:17:56 -0600] "GET /next2/120005079807?check=37593467%2CCOB&check=37593378%2CUAP&box=match&submit=Next HTTP/1.1" 500 1633 "https://mvt.squaretwofinancial.com/newmed/?button=All&submit=Submit" "Mozilla/5.0 (Windows NT 6.1; WOW64; rv:45.0) Gecko/20100101 Firefox/45.0"
在这种情况下,我需要取
37593467
和37593378
。请检查此代码
import re
text = '''11.249.222.103 - - [15/Aug/2016:13:17:56 -0600] "GET /next2/120005079807?check=37593467%2CCOB&check=37593378%2CUAP&box=match&submit=Next HTTP/1.1" 500 1633 "https://mvt.squaretwofinancial.com/newmed/?button=All&submit=Submit" "Mozilla/5.0 (Windows NT 6.1; WOW64; rv:45.0) Gecko/20100101 Firefox/45.0"'''
for match in re.findall("check=(\d+)",text):
print 'Found "%s"' % match
输出:
C:\Users\dinesh_pundkar\Desktop>python demo.py
Found "37593467"
Found "37593378"
两个URL以获取帮助:
import re
text = '''11.249.222.103 - - [15/Aug/2016:13:17:56 -0600] "GET /next2/120005079807?check=37593467%2CCOB&check=37593378%2CUAP&box=match&submit=Next HTTP/1.1" 500 1633 "https://mvt.squaretwofinancial.com/newmed/?button=All&submit=Submit" "Mozilla/5.0 (Windows NT 6.1; WOW64; rv:45.0) Gecko/20100101 Firefox/45.0"'''
for match in re.findall("check=(\d+)",text):
print 'Found "%s"' % match
输出:
C:\Users\dinesh_pundkar\Desktop>python demo.py
Found "37593467"
Found "37593378"
两个URL以获取帮助:
re.findall(r')(?re.findall(r'(?好的,要修改,我如何在…之后的文本上搜索,即,我如何获得匹配项以根据是否找到%2CCOB
或%2CUAP
?好的,要修改,我如何在…之后的文本上搜索,即,我如何获得匹配项以根据是否找到%2CCOB
或%2CUAP显示数字e> ??