Python 在QStackedWidget、pyqt中设置状态更改信号

我有一个来自internet的QStacked小部件代码示例，它为每个孩子生成自己的布局（如下）

现在，我想从所有这些数据中收集数据，稍后再进行处理。例如，我如何知道选中了哪个复选框？此代码 layout.addWidget（QCheckBox（“物理”）.stateChanged.connect（self.state_changed））

给我

流程结束，退出代码为1073741819（0xC0000005）

当你写作时

layout.addWidget(QCheckBox("Physics").stateChanged.connect(self.state_changed))

这不会查找“物理”复选框，但会创建一个新复选框。因为您没有保留对它的Python引用，所以在您离开构造函数后它将被销毁。但是，它仍然连接到一个信号，这会导致不可预测的行为

如果要连接到原始复选框，则需要对其进行引用。像这样：

import sys
from PyQt4.QtCore import *
from PyQt4.QtGui import *

class stackedExample(QWidget):
    def __init__(self):
        super(stackedExample, self).__init__()
        self.leftlist = QListWidget()
        self.leftlist.insertItem(0, 'Contact')
        self.leftlist.insertItem(1, 'Personal')
        self.leftlist.insertItem(2, 'Educational')

        self.stack1 = QWidget()
        self.stack2 = QWidget()
        self.stack3 = QWidget()

        self.stack1UI()
        self.stack2UI()
        self.stack3UI()

        # Renamed self.stack to self.stack since the convention is to start
        # class names with a capital but regular variables with a lower case.
        self.stack = QStackedWidget(self) 
        self.stack.addWidget(self.stack1)
        self.stack.addWidget(self.stack2)
        self.stack.addWidget(self.stack3)

        hbox = QHBoxLayout(self)
        hbox.addWidget(self.leftlist)
        hbox.addWidget(self.stack)

        self.setLayout(hbox)
        self.leftlist.currentRowChanged.connect(self.display)
        self.setGeometry(300, 50, 10, 10)
        self.setWindowTitle('StackedWidget demo')
        self.show()

    def stack1UI(self):
        layout = QFormLayout()
        layout.addRow("Name", QLineEdit())
        layout.addRow("Address", QLineEdit())
        # self.setTabText(0,"Contact Details")
        self.stack1.setLayout(layout)

    def stack2UI(self):
        layout = QFormLayout()
        sex = QHBoxLayout()
        sex.addWidget(QRadioButton("Male"))
        sex.addWidget(QRadioButton("Female"))
        layout.addRow(QLabel("Sex"), sex)
        layout.addRow("Date of Birth", QLineEdit())

        self.stack2.setLayout(layout)

    def stack3UI(self):
        layout = QHBoxLayout()
        layout.addWidget(QLabel("subjects"))
        self.physicsCheckBox = QCheckBox("Physics")
        layout.addWidget(self.physicsCheckBox)
        self.physicsCheckBox.stateChanged.connect(self.physicsCheckBoxStateChanged)

        layout.addWidget(QCheckBox("Maths"))
        self.stack3.setLayout(layout)


    def physicsCheckBoxStateChanged(self, state):
        isChecked = bool(state) # Convert from Qt.CheckState
        print("physicsCheckBox: {}".format(isChecked))

    def display(self, i):
        self.stack.setCurrentIndex(i)


def main():
    app = QApplication(sys.argv)
    ex = stackedExample()
    sys.exit(app.exec_())


if __name__ == '__main__':
    main()

我将

self.Stack

重命名为

self.Stack

。它是一种Python约定，允许类定义以大写字符和正则变量开头，函数以小写字母开头

当你写作时

layout.addWidget(QCheckBox("Physics").stateChanged.connect(self.state_changed))

这不会查找“物理”复选框，但会创建一个新复选框。因为您没有保留对它的Python引用，所以在您离开构造函数后它将被销毁。但是，它仍然连接到一个信号，这会导致不可预测的行为

如果要连接到原始复选框，则需要对其进行引用。像这样：

import sys
from PyQt4.QtCore import *
from PyQt4.QtGui import *

class stackedExample(QWidget):
    def __init__(self):
        super(stackedExample, self).__init__()
        self.leftlist = QListWidget()
        self.leftlist.insertItem(0, 'Contact')
        self.leftlist.insertItem(1, 'Personal')
        self.leftlist.insertItem(2, 'Educational')

        self.stack1 = QWidget()
        self.stack2 = QWidget()
        self.stack3 = QWidget()

        self.stack1UI()
        self.stack2UI()
        self.stack3UI()

        # Renamed self.stack to self.stack since the convention is to start
        # class names with a capital but regular variables with a lower case.
        self.stack = QStackedWidget(self) 
        self.stack.addWidget(self.stack1)
        self.stack.addWidget(self.stack2)
        self.stack.addWidget(self.stack3)

        hbox = QHBoxLayout(self)
        hbox.addWidget(self.leftlist)
        hbox.addWidget(self.stack)

        self.setLayout(hbox)
        self.leftlist.currentRowChanged.connect(self.display)
        self.setGeometry(300, 50, 10, 10)
        self.setWindowTitle('StackedWidget demo')
        self.show()

    def stack1UI(self):
        layout = QFormLayout()
        layout.addRow("Name", QLineEdit())
        layout.addRow("Address", QLineEdit())
        # self.setTabText(0,"Contact Details")
        self.stack1.setLayout(layout)

    def stack2UI(self):
        layout = QFormLayout()
        sex = QHBoxLayout()
        sex.addWidget(QRadioButton("Male"))
        sex.addWidget(QRadioButton("Female"))
        layout.addRow(QLabel("Sex"), sex)
        layout.addRow("Date of Birth", QLineEdit())

        self.stack2.setLayout(layout)

    def stack3UI(self):
        layout = QHBoxLayout()
        layout.addWidget(QLabel("subjects"))
        self.physicsCheckBox = QCheckBox("Physics")
        layout.addWidget(self.physicsCheckBox)
        self.physicsCheckBox.stateChanged.connect(self.physicsCheckBoxStateChanged)

        layout.addWidget(QCheckBox("Maths"))
        self.stack3.setLayout(layout)


    def physicsCheckBoxStateChanged(self, state):
        isChecked = bool(state) # Convert from Qt.CheckState
        print("physicsCheckBox: {}".format(isChecked))

    def display(self, i):
        self.stack.setCurrentIndex(i)


def main():
    app = QApplication(sys.argv)
    ex = stackedExample()
    sys.exit(app.exec_())


if __name__ == '__main__':
    main()

我将

self.Stack

重命名为

self.Stack

。它是一种Python约定，允许类定义以大写字符和正则变量开头，函数以小写字母开头