在python中，从defaultdict（列表）中的一个键的值中弹出一个键

我有一个

defaultdict（lambda:defaultdict（list））

我有以下代码：

def create_jenkins_job_dict(all_jobs):
    jenkins_job_dict = defaultdict(lambda: defaultdict(list))
    for job in all_jobs:
        if job.startswith("djin_a"):
            stackname = job.split('_', 2).pop(2)
            lz = job.split('_', 2).pop(1)[1:]
            stack_info = parse_stack_info(stackname, lz)
            if stack_info is not None:
                for key, value in stack_info.items():
                    if (value == "up"):
                        jenkins_job_dict[lz][stackname].append(key)
    return jenkins_job_dict

all_jobs = ['cost_explorer', 'cucumber', 'cucumber_reporter', 'cucumber_stacks_cleanup', 'cucumber_stacks_single_account', 'cucumber_stacks_update', 'deptwo.0-workflow', 'dispatcher-policy-setup', 'djin_abuild_active_directory_iandp_domains', 'djin_abuild_artifactory', 'djin_abuild_barrage_slaves', 'djin_abuild_cf_test_1', 'djin_abuild_epam', 'djin_abuild_epportal', 'djin_abuild_gate', 'djin_abuild_groups', 'djin_abuild_hostname_dispatcher_2', 'djin_abuild_jenkins_slaves', 'djin_abuild_netapp_ontap', 'djin_abuild_papi', 'djin_abuild_pibsec_se', 'djin_abuild_sonar_slave', 'djin_abuild_sonarqube', 'djin_acntsvc_category_manager', 'djin_acntsvc_consumer_search_marklogic_db', 'djin_acntsvc_searchh'] # list of names of jobs in jenkins.
jenkins_job_dict = create_jenkins_job_dict(all_jobs) # basically produces the above dict.
while jenkins_job_dict:
    stack_list = jenkins_job_dict.pop(min(jenkins_job_dict,key=jenkins_job_dict.get))
    stack = stack_list.pop(min(stack_list, key=stack_list.get))
    print (stack)

---

这并不能满足我的需要，什么是最适合的方式呢？

这就是你想要的：

outer={'a':{'b':[1,2,3], 'c':[4,5,6]}, 'd':{'e':[7,8,9], 'f':[10,11,12]}}
while outer:
    outer_key, inner = outer.popitem()
    while inner:
        inner_key, inner_value = inner.popitem()

---

“按此顺序排列”：根据定义，字典（即哈希表）是无序的。如果您希望按特定顺序访问键和值，则应先按您希望的顺序（例如在列表中）在其他地方对键进行排序，以使其可复制，您能否提供创建此

jenkins_job_dict

字典的代码？@Niema Moshiri这就是为什么他/她使用
集合中的
默认dict
而不是内置的
dict
类型
@NiemaMoshiri-它不必订购，只需要一次弹出一个。@Tony我想
defaultdict
也是无序的？我想，
OrderedDict
是唯一订购的字典。谢谢！我知道我可以用一种更简单的方法重现我的问题。
def create_jenkins_job_dict(all_jobs):
    jenkins_job_dict = defaultdict(lambda: defaultdict(list))
    for job in all_jobs:
        if job.startswith("djin_a"):
            stackname = job.split('_', 2).pop(2)
            lz = job.split('_', 2).pop(1)[1:]
            stack_info = parse_stack_info(stackname, lz)
            if stack_info is not None:
                for key, value in stack_info.items():
                    if (value == "up"):
                        jenkins_job_dict[lz][stackname].append(key)
    return jenkins_job_dict

all_jobs = ['cost_explorer', 'cucumber', 'cucumber_reporter', 'cucumber_stacks_cleanup', 'cucumber_stacks_single_account', 'cucumber_stacks_update', 'deptwo.0-workflow', 'dispatcher-policy-setup', 'djin_abuild_active_directory_iandp_domains', 'djin_abuild_artifactory', 'djin_abuild_barrage_slaves', 'djin_abuild_cf_test_1', 'djin_abuild_epam', 'djin_abuild_epportal', 'djin_abuild_gate', 'djin_abuild_groups', 'djin_abuild_hostname_dispatcher_2', 'djin_abuild_jenkins_slaves', 'djin_abuild_netapp_ontap', 'djin_abuild_papi', 'djin_abuild_pibsec_se', 'djin_abuild_sonar_slave', 'djin_abuild_sonarqube', 'djin_acntsvc_category_manager', 'djin_acntsvc_consumer_search_marklogic_db', 'djin_acntsvc_searchh'] # list of names of jobs in jenkins.
jenkins_job_dict = create_jenkins_job_dict(all_jobs) # basically produces the above dict.
while jenkins_job_dict:
    stack_list = jenkins_job_dict.pop(min(jenkins_job_dict,key=jenkins_job_dict.get))
    stack = stack_list.pop(min(stack_list, key=stack_list.get))
    print (stack)

outer={'a':{'b':[1,2,3], 'c':[4,5,6]}, 'd':{'e':[7,8,9], 'f':[10,11,12]}}
while outer:
    outer_key, inner = outer.popitem()
    while inner:
        inner_key, inner_value = inner.popitem()