Python 为什么赢了';用户输入是否进入数据库?
到目前为止,我的数据库工作正常。我可以通过Python 为什么赢了';用户输入是否进入数据库?,python,django,database,sqlite,debugging,Python,Django,Database,Sqlite,Debugging,到目前为止,我的数据库工作正常。我可以通过终端手动创建虚拟电子邮件地址,它们将毫无问题地出现 这一次,我想将用户输入转到数据库中。我觉得我已经很熟悉我现在的代码了。但是我一直在Chrome中看到这个错误: 下面是错误: TypeError at /content/content/ 'name' is an invalid keyword argument for this function Request Method: POST Request URL: http://127.0.0.
终端
手动创建虚拟电子邮件地址,它们将毫无问题地出现
这一次,我想将用户输入转到数据库中。我觉得我已经很熟悉我现在的代码了。但是我一直在Chrome
中看到这个错误:
下面是错误
:
TypeError at /content/content/
'name' is an invalid keyword argument for this function
Request Method: POST
Request URL: http://127.0.0.1:8000/content/content/
Django Version: 1.11.3
Exception Type: TypeError
Exception Value:
'name' is an invalid keyword argument for this function
下面是basic.html
:
{% extends "personal/header.html" %}
{% block content %}
<style type="text/css">
h1 {
color: #2e6da4;
font-family: Chalkboard;
}
.text {
text-align: center;
}
</style>
{% for c in content %}
<h1>{{c}}</h1>
{% endfor %}
<div class="form-group">
<form method="POST" action="content/">
{% csrf_token %}
<input type="text" name="textfield">
<button type="submit">Submit</button>
</form>
</div>
{% endblock %}
下面是url.py
:
from django.shortcuts import render
from django.http import HttpResponse
from .models import Email
from django.core.exceptions import *
def index(request):
return render(request, 'personal/home.html')
def contact(request):
if request.method == "GET":
return render(request, 'personal/basic.html', {'content': ['If you would like more information, leave your email.']})
elif request.method == "POST":
email = Email(name=request.POST.get("textfield"))
email.save()
return render(request, 'basic.html')
def search(request):
if request.method == 'POST':
search_id = request.POST.get(name = search_id)
try:
user = Email.objects.get(name=search_id)
# do something with user
html = ("<H1>%s</H1>", user)
return HttpResponse(html)
except Email.DoesNotExist:
return HttpResponse("no such user")
else:
return render(request, 'basic.html')
from django.conf.urls import url
from . import views
urlpatterns = [
url(r'^$', views.index, name='index'),
url(r'^content/', views.contact, name='content'),
]
from django.db import models
class Email(models.Model):
email = models.CharField(max_length=140)
def __str__(self):
return self.email
下面是models.py
:
from django.shortcuts import render
from django.http import HttpResponse
from .models import Email
from django.core.exceptions import *
def index(request):
return render(request, 'personal/home.html')
def contact(request):
if request.method == "GET":
return render(request, 'personal/basic.html', {'content': ['If you would like more information, leave your email.']})
elif request.method == "POST":
email = Email(name=request.POST.get("textfield"))
email.save()
return render(request, 'basic.html')
def search(request):
if request.method == 'POST':
search_id = request.POST.get(name = search_id)
try:
user = Email.objects.get(name=search_id)
# do something with user
html = ("<H1>%s</H1>", user)
return HttpResponse(html)
except Email.DoesNotExist:
return HttpResponse("no such user")
else:
return render(request, 'basic.html')
from django.conf.urls import url
from . import views
urlpatterns = [
url(r'^$', views.index, name='index'),
url(r'^content/', views.contact, name='content'),
]
from django.db import models
class Email(models.Model):
email = models.CharField(max_length=140)
def __str__(self):
return self.email
您需要更换,因为在您的型号中没有字段名称
,但有字段电子邮件
email = Email(name=request.POST.get("textfield"))
到
你希望这能做什么request.POST.get(name=search\u id)
正如错误所说,name
不是该类的有效关键字。模型实际上是否有名称字段?您应该出示模型。请出示您的班级电子邮件@BearBrown model posted.@DanielRoseman model posted感谢您的回复。我试过了,但是现在我得到一个错误,说templatedoesnotextist at/content/content/
。我想你需要将return render(request,'basic.html')
替换为return render(request,'personal/basic.html')
非常感谢!成功了!现在我明白我犯的错误了。再次感谢你,伙计@请别忘了投票支持贝尔斯登的作品,因为答案对你很有用。@hop38我的错误是没有注意到你对StackOverflow很陌生。欢迎来到这里并享受:D