如何在Python中从递归函数返回列表?

如何在Python中从递归函数返回列表?,python,recursion,Python,Recursion,我有以下代码: def primes(n): acc = [] return do_primes(range(2,n,1), acc) def do_primes(xs, acc): if xs: head, tail = xs[0], xs[1:] acc.append(head) do_primes([x for x in xs if x % head != 0], acc) else: return acc 调用代码将导致“无”: >

我有以下代码:

def primes(n):
  acc = []
  return do_primes(range(2,n,1), acc)

def do_primes(xs, acc):
  if xs:
    head, tail = xs[0], xs[1:]
    acc.append(head)
    do_primes([x for x in xs if x % head != 0], acc)
  else:
    return acc
调用代码将导致“无”:

>>> primes(10)
None

您需要再次返回:

def do_primes(xs, acc):
  if xs:
    head, tail = xs[0], xs[1:]
    acc.append(head)
    return do_primes([x for x in xs if x % head != 0], acc)
  else:
    return acc

您需要再次返回:

def do_primes(xs, acc):
  if xs:
    head, tail = xs[0], xs[1:]
    acc.append(head)
    return do_primes([x for x in xs if x % head != 0], acc)
  else:
    return acc