在python中将字符转换为数字

我有一个文本文件，其中包含以下内容：

ABC
AAD
ABE

其中A=5，B=1，C=31，D=101，E=4。 预期产出应为

5,1,31
5,5,101
5,1,4

问题是只有文本文件的最后一行正在转换为数字。 以下是我迄今为止所做的尝试

def replace_all(text, dic):
    for i, j in dic.iteritems():
        text = text.replace(i, j)
    return text

with open('input.txt') as f:
    content = f.readlines()

for i,j in enumerate(content):
  my_text = content[i]
  new_text = ','.join([my_text[i] for i in range(1, len(my_text), 1)])

reps = {'A':'5','B':'1','C':'31','D':'101','E':'4'}
txt = replace_all(new_text, reps)
with open('results.txt', 'a') as my_new_file: 
  my_new_file.write(txt)

---

我做错了什么？

您的代码只考虑上一次迭代中新文本的值，这是最后一行

您应该在for循环中移动所有逻辑

def replace_all(text, dic):
    for i, j in dic.iteritems():
        text = text.replace(i, j)
    return text

with open('input.txt') as f:
    content = f.readlines()

reps = {'A':'5','B':'1','C':'31','D':'101','E':'4'}

with open('results.txt', 'a') as my_new_file: 
    for i,j in enumerate(content):
        my_text = content[i]
        new_text = ','.join([my_text[i] for i in range(1, len(my_text), 1)])

        txt = replace_all(new_text, reps)
        my_new_file.write(txt)

---

你可以把整件事写得更简单

reps = {'A':'5','B':'1','C':'31','D':'101','E':'4'}

with open('input.txt') as f, open('results.txt', 'w') as new_file:
    for line in f:
        new_text = ",".join(reps.get(char, char) for char in line)
        new_file.write(new_text)

---

您可以尝试使用列表理解：

f = open('input.txt').readlines()

f = [i.strip('\n') for i in f]
reps = {'A':'5','B':'1','C':'31','D':'101','E':'4'}

new_list = [[reps[b] for b in i] for i in f]

new_file = open('results.txt', 'a')

for i in new_list:
   new_file.write(','.join(i))
   new_file.write('\n')
new_file.close()

我忍不住：

# create a lookup table
lookup = {
    'A': '5',
    'B': '1',
    'C': '31',
    'D': '101',
    'E': '4'
}

# open the input file and the output file
with open('input.txt', 'r') as f, open('results.txt', 'w') as f_new:
    # for each line...
    for line in f.readlines():
        # ...construct a new line...
        nums = [lookup[character] for character in line.strip()]
        newline = ','.join(nums) + '\n'

        # ... and save the new line to the result file
        f_new.write(newline)

---

在for中的每次迭代中替换新的_文本，而不保存以前的值。您也不会查看范围中每行的第一个字符，它应该从0Ah开始。我真傻。非常感谢。