在Python中为颜色更改程序重复代码
我正在为一个游戏编写一个功能,用户可以按键盘上的一个键,这会将屏幕上绘制的所有对象的颜色更改为该颜色。例如,如果按下在Python中为颜色更改程序重复代码,python,function,encapsulation,Python,Function,Encapsulation,我正在为一个游戏编写一个功能,用户可以按键盘上的一个键,这会将屏幕上绘制的所有对象的颜色更改为该颜色。例如,如果按下g,则所有内容都变为绿色 为此,我可以写: while True: while start==True: clock.tick(30) for event in pygame.event.get(): if event.type == QUIT: pygame.quit()
g
,则所有内容都变为绿色
为此,我可以写:
while True:
while start==True:
clock.tick(30)
for event in pygame.event.get():
if event.type == QUIT:
pygame.quit()
sys.exit()
if event.type == pygame.KEYDOWN:
if event.key == K_SPACE:
start =False
match_start=time.time()
if event.key==K_w:
colour=white
elif event.key==K_g:
colour=green
elif event.key==K_y:
colour=yellow
elif event.key==K_b:
colour=blue
elif event.key==K_r:
colour=red
elif event.key==K_p:
colour=purple
这段代码运行得非常好。但是,我以后需要编写完全相同的代码。为了避免重复,我考虑使用如下函数封装代码:
def set_colour():
if event.key==K_w:
colour=white
elif event.key==K_g:
colour=green
elif event.key==K_y:
colour=yellow
elif event.key==K_b:
colour=blue
elif event.key==K_r:
colour=red
elif event.key==K_p:
colour=purple
while True:
while start==True:
clock.tick(30)
for event in pygame.event.get():
if event.type ==QUIT:
pygame.quit()
sys.exit()
if event.type == pygame.KEYDOWN:
if event.key ==K_SPACE:
start =False
match_start=time.time()
set_colour()
def set_colour(event):
colour = None # Make sure colour is initialized
if event.key == K_w:
colour = white
elif event.key == K_g:
colour = green
elif event.key == K_y:
colour = yellow
elif event.key == K_b:
colour = blue
elif event.key == K_r:
colour = red
elif event.key == K_p:
colour = purple
return colour
随后在程序中,我可以在代码中的几个不同点上多次调用该函数,如下所示:
def set_colour():
if event.key==K_w:
colour=white
elif event.key==K_g:
colour=green
elif event.key==K_y:
colour=yellow
elif event.key==K_b:
colour=blue
elif event.key==K_r:
colour=red
elif event.key==K_p:
colour=purple
while True:
while start==True:
clock.tick(30)
for event in pygame.event.get():
if event.type ==QUIT:
pygame.quit()
sys.exit()
if event.type == pygame.KEYDOWN:
if event.key ==K_SPACE:
start =False
match_start=time.time()
set_colour()
def set_colour(event):
colour = None # Make sure colour is initialized
if event.key == K_w:
colour = white
elif event.key == K_g:
colour = green
elif event.key == K_y:
colour = yellow
elif event.key == K_b:
colour = blue
elif event.key == K_r:
colour = red
elif event.key == K_p:
colour = purple
return colour
不幸的是,这不起作用。我没有收到错误消息,但按下其中一个已定义的键时颜色不会改变。我认为这与需要更多输入数据的函数有关,但我不确定
如果您能提供任何建议,我将不胜感激。您似乎没有将事件传递给您的
set_color()
函数以供其使用,然后您的函数不会返回所选颜色或对其进行任何操作以更改颜色。似乎您的函数只是更改本地颜色
变量,而不是调用函数的范围内的变量
您可能希望更改函数以返回所选的颜色
,并将事件作为如下参数传入:
def set_colour():
if event.key==K_w:
colour=white
elif event.key==K_g:
colour=green
elif event.key==K_y:
colour=yellow
elif event.key==K_b:
colour=blue
elif event.key==K_r:
colour=red
elif event.key==K_p:
colour=purple
while True:
while start==True:
clock.tick(30)
for event in pygame.event.get():
if event.type ==QUIT:
pygame.quit()
sys.exit()
if event.type == pygame.KEYDOWN:
if event.key ==K_SPACE:
start =False
match_start=time.time()
set_colour()
def set_colour(event):
colour = None # Make sure colour is initialized
if event.key == K_w:
colour = white
elif event.key == K_g:
colour = green
elif event.key == K_y:
colour = yellow
elif event.key == K_b:
colour = blue
elif event.key == K_r:
colour = red
elif event.key == K_p:
colour = purple
return colour
然后在调用此函数的代码中,按如下方式执行:
colour = set_colour(event)
您只需将您的
set_color
函数替换为我给出的代码,然后按照我显示的方式调用该函数。只要把代码的位置改成我给你的。