Python 更改网格大小以匹配网格中框的大小
我正在尝试使用matplotlib制作20x20的可视化网格。但是,我在调整网格的大小以适应每个框的大小时遇到困难 这是我的密码:Python 更改网格大小以匹配网格中框的大小,python,matplotlib,Python,Matplotlib,我正在尝试使用matplotlib制作20x20的可视化网格。但是,我在调整网格的大小以适应每个框的大小时遇到困难 这是我的密码: import matplotlib as mpl from matplotlib import pyplot import numpy as np grid = [[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0], [0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1],
import matplotlib as mpl
from matplotlib import pyplot
import numpy as np
grid = [[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0],
[0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1],
[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0],
[1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0],
[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0],
[0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1],
[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0],
[1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0],
[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0],
[0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1],
[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0],
[1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0],
[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0],
[0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1],
[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0],
[1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0],
[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0],
[0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1],
[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0],
[1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0],
]
print (grid)
zvals = grid
# make a color map of fixed colors
cmap = mpl.colors.ListedColormap(['white','black'])
bounds=[-2,-1,1,2]
norm = mpl.colors.BoundaryNorm(bounds, cmap.N)
# tell imshow about color map so that only set colors are used
img = pyplot.imshow(zvals,interpolation='nearest',
cmap = cmap,norm=norm)
# make a color bar
pyplot.colorbar(img,cmap=cmap,
norm=norm,boundaries=bounds,ticks=[0,1])
pyplot.grid(which= 'both')
pyplot.show()
我希望网格的大小为黑匣子。您可以将此部分添加到代码中:
ax = pyplot.gca()
major_ticks = np.arange(0.5, 20, 1)
pyplolt.xticks(rotation=90)
ax.set_xticks(major_ticks)
ax.set_yticks(major_ticks)
ax.grid(which='both')
pyplot.grid(True)
输出:
Ps.通常以这种方式导入pyplot
:import matplotlib.pyplot as plt